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laila [671]
3 years ago
11

Which type of nuclear radiation is being emitted here?

Chemistry
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

b.Beta

Explanation:

mass number remains constant while atomic number has been increased by 1 unit . beta is electron like element where its mass number is 0 and atomic number is -1.

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Why less electro negative elements are taken as central atom​
sladkih [1.3K]

Answer:

The least electronegative elements in the center of lewis structures because an atom in the central position shares more of its electrons than does a terminal atom. Atoms with higher electronegative are generally more reluctant to share their electrons.

Explanation:

3 0
2 years ago
The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,
Mila [183]

Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

\frac {r^+}{r^-}=0.731 .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

r^++r^-=\frac {a}{2}  ...................2

Given that:

Cl^-\ (r^-) = 1.82\ \dot{A}

To find,

K^+\ (r^+) = ? \dot{A}

Using 1 and 2 , we get:

1.731\ r^+=0.731\times \frac {6.28}{2}

<u>Size of the potassium ion = 1.33 Å</u>

4 0
3 years ago
What is the pH of a solution with a [H+] of 1.0 x 10-4 M?
MaRussiya [10]
PH = -log [H+]
pH = -log (1.0x10^-4) = -(-4) = 4 or A
4 0
3 years ago
2. A magnifying glass is an example of a _______ lens.
NISA [10]
<span>The answer to question 2 is C. A magnifying glass is an example of a plano-convex lens, where one side of the lens is flat and the other is a convex curve. The answer to question 3 is either B or C. A converging lens is curved on both sides and so the rays of light coming out of it converge at a point, which is known as the focal point. When the object is inside the focal point, the image is real and inverted. If it is inside the focal point, the image is virtual and upright. Therefore the image in this question will be upright. The focal length is the distance between the image that is being magnified and the centre of the magnifying lens. A real image can only be formed when the object is further away from the lens than the focal length. Therefore, in this question, the image is virtual, as the object is closer to the lens than the focal length. The answer to question 4 is D because the index of refraction cannot be less than 1. The answer to question 5 is D because only concave mirrors can produce real images; other types produce virtual images. For question 6, the answer is D. In the rainbow, each of the colours refracts at a slightly different angle; red has the smallest refractive index and violet the largest. Of the options, orange is closest to red. For question 12, A is the answer. A higher operating temperature is not a reason fluorescent lamps are better than incandescent lamps because they have a lower operating temperature. Question 15: all of these are characteristics of different electromagetic waves. For question 18, B is true - special care must be taken when low illuminance is required to reduce glare. The answer to question 19 is B - a compound microscope makes use of two lenses. For question 20, the answer is 5 meters away. The illuminance (E) is equal to light intensity (I) divided by the square distance from the light source (d). Therefore, 4 = 100/d squared. To switch this around, d squared is equal to 100/4 = 25. Then find the square root of 25, which is 5.</span>
7 0
3 years ago
Read 2 more answers
A car travels at a speed of 80 km/h. Which of the following is correct to convert the speed of the car to hm/s? [1 km = 10 hm, 1
amm1812

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

We are given that car travels with a speed of 80 km/hr and we need to convert it into hm/s.

For that we use the conversions:

1 kilometer = 10 hectometer

And, 1 hour = 3600 seconds

To convert the quantity into hm/s, we multiply the numerator which is 80 by 10 to convert the whole quantity into hm/hr and now, to convert the result into hm/s finally, we divide the result by 3600.

\Rightarrow (\frac{80km1}{hr})(\frac{10hm}{1km})=\frac{80km}{hr}\\\\\Rightarrow (\frac{80km}{hr})(\frac{1hr}{3600s})=\frac{80hm}{3600s}

Hence, the correct answer is option D.

4 0
3 years ago
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