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fiasKO [112]
3 years ago
5

Solve 1 expression Please do everything in great detail (well, just a very great detail)

Mathematics
1 answer:
monitta3 years ago
5 0
Remember the distributive property
a(b+c)=ab+ac

so
first distribute
(2/3a-0.8)(a-0.8)=0.64
focus on the left side

(2/3a-0.8)(a-0.8)=
(a)(2/3a-0.8)+(-0.8)(2/3a-0.8)=
(2/3a^2)+(-0.8a)+(-1.6/3a)+(0.64)=
2/3a^2-4/3a+0.64
now we do
2/3a^2-4/3a+0.64=0.64
minus 0.64 both sides
2/3a^2-4/3a=0
factor
(a)(2/3a-4/3)=0
set each to zero
a=0

2/3a-4/3=0
add 4/3 both sides
2/3a=4/3
times 3 bohth sides
2a=4
divide 2
a=2

a=0 or 2

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Una fábrica produce tres tipos de balones de fútbol, con un costo mensual de
Varvara68 [4.7K]

Answer:

Se fabricaron:

1000 balones de los que cuestan $20

75 balones de los que cuestan $30

50 balones de los que cuestan $40

Step-by-step explanation:

Vamos a definir las variables:

x = número de balones de $100.00 vendidos.

y = número de balones de $120.00 vendidos

z = número de balones de $160,00 vendidos.

Sabemos que se producen 1125 balones, entonces:

x + y + z = 1125

y el costo de producción es $24,250, conociendo el costo de cada balón podemos escribir:

x*$20 + y*$30 + z*$40 = $24,250

Y también sabemos que la ganancia mensual es $92,750

Ganancia es la diferencia entre el dinero total recibido y los costos, entonces:

x*$100 + y*$120 + z*$160 - $24,250 =  $92,750

x*$100 + y*$120 + z*$160 = $92,750 + $24,250

x*$100 + y*$120 + z*$160 = $117,000

Entonces tenemos un sistema de 3 ecuaciones:

x + y + z = 1125

x*$20 + y*$30 + z*$40 = $24,250

x*$100 + y*$120 + z*$160 = $117,000

Para resolver esto debemos comenzar por aislar alguna variable en alguna de las ecuaciones, yo comenzare aislando x en la primera ecuación:

x = 1125 - y - z

Ahora podemos reemplazar esto en las otras dos ecuaciones para obtener:

(1125 - y - z)*$20 + y*$30 + z*$40 = $24,250

(1125 - y - z)*$100 + y*$120 + z*$160 = $117,000

Si simplificamos esto obtenemos:

$22,500 + y*$10 + z*$20 = $24,250

$112,500 + y*$20 + z*$60 =  $117,000

Ahora de vuelta, debemos aislar una variable en una de las ecuaciones, si aislamos y en la primera ecuación obtenemos:

y*$10 = $24,250 - $22,500 -  z*$20

y = ($1,750 - z*$20)/$10

y = 175 - 2*z

Reemplazando esto en la otra ecuación obtenemos:

$112,500 + (175 - 2*z)*$20 + z*$60 =  $117,000

Ahora podemos resolver esto para z.

(175 - 2*z)*$20 + z*$60 =  $117,000 - $112,500

(175 - 2*z)*$20 + z*$60 = $4,500

$3,500 - z*$40 + z*$60 = $4,500

$3,500 + z*$20 = $4,500

z*$20 = $4,500 - $3,500 = $1,000

z = $1,000/$20 = 50

Entonces tenemos 50 balones de los que cuestan $40.

Usando la ecuación y = 175 - 2*z podemos encontrar el valor de y.

y = 175 - 2*50 = 75

Entonces tenemos 75 balones de los que cuestan $30.

Usando la ecuación x = 1125 - y - z podemos encontrar el valor de x.

x = 1125 - 75 - 50 = 1000

tenemos 1000 balones de $20.

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3 years ago
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marysya [2.9K]

Answer:30

Step-by-step explanation:

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First year of high school heh need a little help​
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Answer:

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Step-by-step explanation:

(12 + 3)x = 12x + 3x = 15x

(12 + 3x)x = 12x + 3x²

15x

12x + 3x = 15x

They all equal 15x except for (12 + 3x)x

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Step-by-step explanation:

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Answer: b || explanation
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