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3 years ago

Solve 1 expression Please do everything in great detail (well, just a very great detail)

Mathematics

1 answer:

monitta3 years ago

5 0

Remember the distributive property
a(b+c)=ab+ac

so
first distribute
(2/3a-0.8)(a-0.8)=0.64
focus on the left side

(2/3a-0.8)(a-0.8)=
(a)(2/3a-0.8)+(-0.8)(2/3a-0.8)=
(2/3a^2)+(-0.8a)+(-1.6/3a)+(0.64)=
2/3a^2-4/3a+0.64
now we do
2/3a^2-4/3a+0.64=0.64
minus 0.64 both sides
2/3a^2-4/3a=0
factor
(a)(2/3a-4/3)=0
set each to zero
a=0

2/3a-4/3=0
add 4/3 both sides
2/3a=4/3
times 3 bohth sides
2a=4
divide 2
a=2

a=0 or 2

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Classify the following polynomial function, −3x(x2−4)(2x2+5)based on degree and number of terms.

Free_Kalibri [48]

Answer:

Quintic Trinomial (2nd option)

Step-by-step explanation:

We know that this is a quintic polynomial because the degrees add up to 5. If we expand the polynomial, we have $-3x(x^2-4)(2x^2+5)=(-3x^3-12x)(2x^2+5)=-6x^5-45x^3-24x^3-60x=-6x^5-69x^3-60x$

So, there are 3 terms, which is a trinomial.

5 0

2 years ago

Find x (steps pls) | x - 7| = 2 (i dunt understand the | in the questions)

kirill [66]

these two bars | | mean absolute value

here's how to find x

| x - 7| = 2

first apply the absolute rule

x - 7 = 2 x - 7 = -2

in both equations add 7 on both sides

x - 7 + 7 = 2 + 7 x - 7 + 7 = -2 + 7

then simplify the expressions

x = 9 x = 5

now combine these two solutions to get your answer

x = 9 or x = 5

hopefully my explanation helps

3 0

3 years ago

Nine less than the quotient of twice a number and four.

Leno4ka [110]

Answer:

-1

Step-by-step explanation:

Twice a number of 4 equals 8

4×2=8

less than 9 of the quotient (answer) of twice a number of 4, is -1

8-9= -1

4 0

3 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

Given equation:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

4 0

2 years ago

PLEASE HELP! The question is in the picture, i need to answer URGENTLY!

Andrej [43]

Kim is 43 Jordan is 50

200÷4=50
50-7=43

200÷4-7=x

4 0

3 years ago