3×9
n+1
−9×3
2n
=
3×3
2n+3
−(3
2
)
n+1
3×(3
2
)
n+1
−3
2
×3
2n
=
3
1+2n+3
−3
2n+2
3
1+2n+2
−3
2+2n
=
3
4+2n
−3
2n+2
3
3+2n
−3
2+2n
=
3
2n
(3
4
−3
2
)
3
2n
(3
3
−3
2
)
=
81−9
27−9
=
72
18
=
4
1
Answer:
n = 32
Step-by-step explanation:
<u><em>Given:</em></u>
<u><em></em></u>
<u><em>Solve:</em></u>
<em />
<em />



~![\mathrm{[Kavinsky]}](https://tex.z-dn.net/?f=%5Cmathrm%7B%5BKavinsky%5D%7D)
B I think this needs to be longer answer but b
A circle is centered at K(0,0)K(0,0)K, left parenthesis, 0, comma, 0, right parenthesis. The point U(6,-4)U(6,−4)U, left parenth
Lapatulllka [165]
Answer:
inside the circle
Step-by-step explanation:
Khan Academy
Answer:
Step-by-step explanation: