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How can the Associative, Commutative, and Distributive Properties be applied when performing operations on complex numbers and p

ozzi

By using Associative, Commutative, and Distributive Properties in performing operations on complex numbers and polynomials, you would be able to simplify correctly and simply. To combine complex numbers, you must distribute any coefficients in front of the parentheses. Then identify and<span>combine like terms by combining the real number parts and the imaginary number parts separately.</span>

8 0

3 years ago

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HELP ASAP PLEASE WILL MARK BRAINIEST

allsm [11]

It has to be 45 degrees pal

6 0

3 years ago

Given h()<br> - 4x - 4, solve for a when h(x)<br> -8.

Ilia_Sergeevich [38]

Answer:

28

Step-by-step explanation:

this is a function

if h(x) is -8 you would plug it in for x:

-4(-8) -4 a negative × a negative is a positive

32- 4= 28

7 0

3 years ago

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Pleasee help me, I don’t get it

Aleks [24]

Answer:

x = 4 sqrt(5)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

8^2 + x^2 = 12^2

64+ x^2 =144

Subtract 64 from each side

x^2 = 144-64

x^2 =80

Take the square root of each side

sqrt(x^2) = sqrt(80)

x = sqrt(16*5)

x = 4 sqrt(5)

8 0

2 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago