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GalinKa [24]
4 years ago
8

A ver y Strong wind is Blowing over a big lake. A flock of geese begins their 5(10)3 meter journey home over the lake. For every

5 (10)2 meters the geese fly over the lake, they are blown back 5 (10)1 meters by the wind. It takes three minutes for the geese to fly 5 (10)2 meters forward and be blown back 5 (10)1 meters. If the geese begin flying across the lake at eleven-thirty in the morning, what time sólo they reach Home? Show all of your mathematical thinking.
Mathematics
1 answer:
maksim [4K]4 years ago
7 0
<span>The geese are required to make a 5000 meter journey. For every 500 meters they travel forward they are blown back 50 meters. Therefore rather than traveling forward 500 meters, they travel forward only 450 meters. Presumably this happens during the whole course of each section of the flight, so when they travel fractions of the distance they are blown back in the same proportion. Since each 450 meter gain requires 3 minutes, and it will take 11.11111 450 meter sections of flight, it will take 33.333333 minutes. Since they leave at 11:30, they will arrive at 12:03 and roughly twenty seconds.</span>
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Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :

[H^{+}]=\sqrt{Ka . Ma}

where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.

Since we know the concentration of H+, the pH can be calculated by using

pH = -log[H+]

From question above, we know that :

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By using the equation, we can determine the concentration of [H+]

[H+] = √(Ka . Ma)

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[H+] = 6.12 x 10¯⁴ M

Substituting the value of [H+] to get the pH

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\huge\textsf{Therefore, your answer should be: }

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