What subatomic particle has a nuetral charge?

amelia goes for mountering with some selected friend of her batch .Intially she is scared of it .Her trainer John tells her that

IRISSAK [1]

Answer:

나쁜 소식 원인 나는 ques 원인 메신저 한국어 내가 캔트 unfmder 대답 할 수 없습니

5 0

3 years ago

A 15,000 kg rocket traveling at +230 m/s turns on its engines. Over a 6.0 s period it burns 1,000 kg of fuel. An observer on the

lesya692 [45]

Answer:

a) $v = 312.791\,\frac{m}{s}$ , b) $a = 13.333\,\frac{m}{s^{2}}$

Explanation:

The problem is asking the rocket velocity and acceleration at t = 6 s.

a) The general equation of the rocket is:

$v=v_{o} -v_{ex}\cdot \ln \frac{m}{m_{o}}$

$v = 230\,\frac{m}{s}-(1200\,\frac{m}{s} )\cdot \ln \frac{14000\,kg}{15000\,kg}$

$v = 312.791\,\frac{m}{s}$

b) The acceleration experimented by the rocket is:

$a = \frac{v_{ex}}{m_{o}}\cdot \frac{dm}{dt}$

$a = \frac{1200\,\frac{m}{s} }{15000\,kg}\cdot \frac{1000\,kg}{6\,s}$

$a = 13.333\,\frac{m}{s^{2}}$

3 0

4 years ago

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A 20N force pulls to the right and friction pulls 5N.<br> If the mass is 5kg, find the acceleration

torisob [31]

So obviously the 20N pulls more than the 5N. Friction opposes direction of motion, so the 5N opposes the 20N and the two forces are against each other.

Net force would be in the direction of the 20N force: 20N - 5N = 15N.

Force = mass*acceleration
15 = (5)*acceleration
acceleration = 3m/s^2

5 0

3 years ago

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An individual is nearsighted; his near point is 13.0 cm and his far point is 50.4 cm. what lens power is needed to correct his n

Colt1911 [192]

Answer:

= -1.984 Diopters

Explanation:

The lens should form an upright, virtual image at the far point.

Therefore;

The image distance, V will be -50.4 cm, since the image is virtual.

For objects at very far distant the object distance,u, will be ∞ ; This means that focal length, f, will be equivalent to image distance, v, that is -50.4 cm

Therefore; f = -50.4/100 = -0.504 m

But, since Power of a lens, P, is given by the reciprocal of focal length in meters, (1/f)

Then, power will be given by;

Power = 1/f

= 1/-0.504 m

=- 1.984

Power is measured in Diopters

Hence <u>= -1.984 Diopters</u>

5 0

3 years ago

A ship is towed through a narrow channel by applying forces to three ropes attached to its bow. Determine the magnitude and orie

Y_Kistochka [10]

This question is solved using an available similar problem as data provided for the forces was not given.

Repeat the same steps outlined for your problem.

Regards.

Answer:

F = 1.598 KN , Q = 90 degree (+ y-axis)

Explanation:

Sum of Forces in x-direction to the left (+)

2 cos (30) + 3cos (60) + F*cos (Q) = F_a ..... 1

Sum of Forces in y-direction to the up (+)

2 sin (30) + F*sin (Q) - 3 sin (60) ...... 2

Using Eq 2 and solve:

F*sin (Q) = 1.598 KN

F_min when sin (Q) is max, max possible value of sin(Q) = 1 @ Q = 90 degrees.

Hence,

F_min = 1.598 KN

Using Eq 1 @ Q = 90 degrees and F = 1.598 KN:

F_a = 2 cos (30) + 3cos (60) = 3.2 KN

6 0

3 years ago

What subatomic particle has a nuetral charge?​

What subatomic particle has a nuetral charge?