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Dmitriy789 [7]
4 years ago
15

You attach a 1.90 kg mass to a horizontal spring that is fixed at one end. You pull the mass until the spring is stretched by 0.

400 m and release it from rest. Assume the mass slides on a horizontal surface with negligible friction. The mass reaches a speed of zero again 0.600 s after release (for the first time after release). What is the maximum speed of the mass (in m/s)
Physics
1 answer:
Gre4nikov [31]4 years ago
6 0

Answer:

2.09 m/s

Explanation:

As the  spring is stretched initially , and the mass released from rest i.e v=0. Also, The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.600 s. This illustrates half oscillation of the system.

Therefore, for the period of a full oscillation of the system

T= 2t => 2(0.6)=> 1.2 s

As the frequency is the reciprocal of the period, we have

f= 1/T => 1/1.2

f= 0.833 Hz

The angular frequency'ω' is given by,

ω= 2πf => 2π x 0.833=>5.23 rad/s

For the maximum velocity of the object  in a spring-mass system:

V(_{max} )= Aω

where A is the amplitude of the oscillation. As here, the amplitude of the motion corresponds to the initial displacement of the object (A=0.400 m)

V(_{max} )= 0.4 x 5.23 =>2.09 m/s

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Answer:

Explanation:

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If Q₁ becomes three times , force will become 3 times . Hence force becomes .3 N in the first case.

Force F = .3 N

If charge becomes one fourth , force also becomes one fourth .

F= \frac{.1}{4}

= .025 N.

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In an atom, electrons ____.
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Two blocks with masses M1 and M2 hang one under the other.
Anna35 [415]

Answer:

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Real world situation to explain the relationship between work and power
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-- Work = (force) times (distance).

    You and your partner both lifted the same amount of weight
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In a mass spectrometer, a single-charged particle (charge e) has a speed of 1.0 × 10 6 m/s and enters a uniform magnetic field o
Nonamiya [84]

Answer:

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   The  speed of the charge is  v   = 1.0 *10^{6} \  m/s

    The  magnetic field is  B = 0.20 \ T

     The radius is r  =  0.02 \ m

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So  

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substituting values

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