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Valentin [98]
3 years ago
6

A weight lifter with a mass of 132kg is standing on the floor supporting a large dumbbell. If the dumbbell has a weight of 450N,

what is the normal force applied to the weight lifter from the floor?
Physics
1 answer:
earnstyle [38]3 years ago
4 0
We know that the weight G is a force calculated as:
G [N] = m [kg] · g [m/s²], where m is mass in kilograms and g is the gravitational acceleration, equal to 9.8 m/s².

Now we calculate the weight of the weightlifter:
Gwl = 132 · 9.8 = 1293.6 N

The normal force applied to the weightlifter from the floor is the sum between the weight of the weightlifter and the weight of the dumbbell:
Gn = Gwl + Gdb = 1293.6 + 450 = 1743.6 N
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Answer:

In both cases the height is greater than 10.3 m

Explanation:

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If we use the definition of density

      ρ = m / V

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For this case the density of the gases is

       ρ' = 0.9 \rho_{water}

       h =\frac{P}{0.9 \ \rho_{water} g}

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     h = 11.3 m

      ρ’= 0.8 \rho_{water}

       h = 1 105 / (0.8 1000 9.8

       h = 12.8 m

In both cases the height is greater than 10.3 m

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