What is the area of this figure?

Mathematics

1 answer:

coldgirl [10]3 years ago

3 0

Answer: 102

-----------------------------------------------

We'll use the formula
A = h*(b1+b2)/2
where
A = area of trapezoid
h = height
b1 & b2 are the parallel bases

In this case,
b1 = 6+7 = 13
b2 = 21
h = 6

Making the area to be
A = h*(b1+b2)/2
A = 6*(13+21)/2
A = 6*(34)/2
A = 204/2
A = 102

Side Note: We don't use the slanted side of 10 cm at all

You might be interested in

You have $15 to spend in a candy store. If Kitkat cost $0.75 each and mini Snickers are $0.25 each.

zhuklara [117]

Answer:

1. 60 snickers

2. 20 KitKats

i cannot anwser 3 cause its not showing up somehow. Sorry.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Y = x² + 6x + 3

olganol [36]

Vertex is at $\left(-3,-6\right)$

y-intercept is 3.

The parabola opens up.

Step-by-step explanation:

The graph of the equation is hereby attached in the answer area.

Vertex is the point on the parabola where the graph crosses its axis of symmetry. The axis of symmetry here( $x =-3$ ), is shown with the dotted line in the graph attached.

y-intercept is defined as the value of y where the graph crosses the y-axis. In other words, when $x=0$ . Putting

And, the graph opens up as shown the graph figure as well. It is also evident from the co-efficient of $x$ in the given equation $y =x^{2} + 6x + 3$ . Here, co-efficient of