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3 years ago

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What is the domain of g?

1 answer:

sattari [20]3 years ago

8 0

Answer:

{ x | -7 ≤ x ≤ 4 }

Step-by-step explanation:

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(I don't usually ask for help on Brainly, but I really suck at Radicals and I need help.

Artemon [7]

My first answer. Lots of parts for five minutes. Took me that long to decode the question. It looks like your multiplying where you're taking roots.

$(\sqrt[4]{7})^5 = (7^{\frac 1 4})^5 = 7^{\frac 5 4}
$

<span>Choice A. Next
</span>
$(3^{2/3})^{1/6} = 3^{ \frac 2 3 \times \frac 1 6 } = 3^{\frac 1 9} = \sqrt[9]{ 3} 


$

Choice B.

$\dfrac {2^{3/4} } {2 ^{1/2} } = 2^{3/4 - 1/2} = 2^{1/4} = \sqrt[4] {2}
$

Choice C

6 0

3 years ago

Read 2 more answers

Hello help me with this question thanks in advance

Ede4ka [16]

$\bold{\huge{\green{\underline{ Solutions }}}}$

<h3><u>Answer </u><u>1</u><u>1</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

$\sf{HM = 5 cm }$

<u>In </u><u>square </u><u>all </u><u>sides </u><u>of </u><u>squares </u><u>are </u><u>equal </u>

<u>The </u><u>perimeter </u><u>of </u><u>square </u>

$\sf{ = 4 × side }$

$\sf{ = 4 × 5 }$

$\sf{ = 20 cm }$

Thus, The perimeter of square is 20 cm

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

$\sf{MX = 3.5 cm }$

<u>In </u><u>square</u><u>,</u><u> </u><u>diagonals </u><u>are </u><u>equal </u><u>and </u><u>bisect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u>

<u>Here</u><u>, </u>

$\sf{MX = MT/2}$

$\sf{MT = 2 * 3.5 }$

$\sf{MT = 7 cm}$

Thus, The MT is 7cm long

Hence, Option C is correct .

<h3><u>Answer </u><u>1</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>measure </u><u>of </u><u>Ang</u><u>l</u><u>e</u><u> </u><u>MAT</u>

<u>All </u><u>angles </u><u>of </u><u>square </u><u>are </u><u>9</u><u>0</u><u>°</u><u> </u><u>each </u>

<u>From </u><u>above </u>

$\sf{\angle{MAT = 90° }}$

Thus, Angle MAT is 90°

Hence, Option B is correct .

<h3><u>Answer </u><u>1</u><u>4</u><u> </u><u>:</u><u>-</u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

<u>All </u><u>the </u><u>angles </u><u>of </u><u>square </u><u>are </u><u>equal </u><u>and </u><u>9</u><u>0</u><u>°</u><u> </u><u>each </u>

<u>Therefore</u><u>, </u>

$\sf{\angle{MHA = }}{\sf{\angle{ MHT/2}}}$

$\sf{\angle{MHA = 90°/2}}$

$\sf{\angle {MHA = 45°}}$

Thus, Angle MHA is 45°

Hence, Option A is correct

<h3><u>Answer </u><u>1</u><u>5</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Refer the above attachment for solution

Hence, Option A is correct

<h3><u>Answer </u><u>1</u><u>6</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Both a and b

<u>The </u><u>median </u><u>of </u><u>isosceles </u><u>trapezoid </u><u>is </u><u>parallel </u><u>to </u><u>the </u><u>base</u>
<u>The </u><u>diagonals </u><u>are </u><u>congruent </u>

Hence, Option C is correct

<h3><u>Answer </u><u>1</u><u>7</u><u> </u><u>:</u><u>-</u></h3>

In rhombus PALM,

<u>All </u><u>sides </u><u>and </u><u>opposite </u><u>angles </u><u>are </u><u>equal </u>

Let O be the midpoint of Rhombus PALM

<u>In </u><u>Δ</u><u>OLM</u><u>, </u><u>By </u><u>using </u><u>Angle </u><u>sum </u><u>property </u><u>:</u><u>-</u>

$\sf{35° + 90° + }{\sf{\angle{ OLM = 180°}}}$

$\sf{\angle{OLM = 180° - 125°}}$

$\sf{\angle{ OLM = 55° }}$

<u>Now</u><u>, </u>

$\sf{\angle{OLM = }}{\sf{\angle{OLA}}}$

<u>OL </u><u>is </u><u>the </u><u>bisector </u><u>of </u><u>diagonal </u><u>AM</u>

<u>Therefore</u><u>, </u>

$\sf{\angle{ PLA = 55° }}$

Thus, Angle PLA is 55° .

Hence, Option C is correct

8 0

2 years ago

Jonathan wants to paint the bottom of is swimming pool the color blue. The swimming pool has a diameter of 50 feet. How many squ

vivado [14]

Answer:

45ml4 544544554n

;lolokStep-by-step explanation:

3 0

3 years ago

What is the equation of a line that contains point (2, -1) and is parallel to<br> y =<br> *x+3<br> ?

prohojiy [21]

Answer:

6 degrees

Step-by-step explanation:

8 0

3 years ago

Natalie added 20 pieces of candy to a bowl. Two days later, half of the candy in the bowl is gone. If there are 14 pieces left i

Salsk061 [2.6K]

Answer:

8 pieces of candy

Step-by-step explanation:

Take the original amount of candy in the bowl to be $x$ .

It says that 20 pieces of candy were added, therefore there are $x+20$ pieces of candy in the bowl.

Half of the candy is gone, therefore $\frac{x+20}{2}$ pieces of candy are left in the bowl.

After half of the candy is gone, there are 14 pieces left, so we can say that $\frac{x+20}{2} =14$

Solve for $x$ :

$x+20 = 28$

$x=8$

8 0

3 years ago