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mafiozo [28]
3 years ago
12

What is the lateral area and the surface area of the cone shown below? Round the answer to the nearest tenth. Figure is not draw

n to scale.

Mathematics
2 answers:
Lelu [443]3 years ago
5 0

Answer:

LA = 1,187.5 ft^{2} and SA = 1,803.3 ft^{2}

Step-by-step explanation:

We are given, the radius 'r' of the cone is 14 ft and the slant height 'l' is given by 27 ft.

Now, we know that the formula for the lateral area = \pi *r*l

i.e. lateral are = \pi *14*27

i.e. lateral area = 1187.52 ft^{2}

Hence, lateral area rounded off to nearest tenth is 1187.5 ft^{2}.

Next, we know the formula for surface area of a cone = \pi *r*(l+r)

i.e. surface area = \pi*14*(27+14)

i.e. surface area = 1803.27 ft^{2}

Hence, the surface area rounded off to the nearest tenth is 1803.3 ft^{2}.

Ann [662]3 years ago
4 0
LA= \pi rs= \pi 14(27)=1187.5 ft ^{2}
SA=LA+ \pi  r^{2} =1187.5+ \pi (14)^{2} =1187.5+ \pi 196= 1187.5+615.8=1803.3ft^{2}

Hope that helps.
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Vamos lá. 

<span>Pede-se para determinar o parâmetro "m" da equação abaixo, sabendo-se que uma raiz é nula e a outra é positiva: </span>

<span>x² + mx + m² - m - 12 = 0 </span>

<span>Veja que se uma raiz é nula (é igual a zero), então vamos substituir o "x" por "0", na equação acima: </span>

<span>0² + m*0 + m² - m - 12 = 0 </span>
<span>0 + 0 + m² - m - 12 = 0 </span>
<span>m² - m - 12 = 0 ------resolvendo essa equação do 2º grau você encontrará as seguintes raízes: </span>

<span>m' = -3 </span>
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<span>Dessa forma, vamos substituir "m" por (-3) e por 4 e ver se a equação terá uma raiz nula e outra positiva. Vamos ver? </span>

<span>Substituindo "m" por "-3", ficamos com: </span>

<span>x² - 3x + (-3)² - (-3) - 12 = 0 </span>
<span>x² - 3x + 9 + 3 - 12 = 0 </span>
<span>x² - 3x +12 - 12 = 0 </span>
<span>x² - 3x = 0 <------Veja que as raízes dessa equação são: x' = 0 e x'' = 3 </span>
<span>Veja que para m = -3, a equação se verifica, pois temos uma raiz igual a "0" e a outra positiva (igual a 3). </span>

<span>Agora vamos substituir "m" por 4 na equação original: </span>

<span>x² + 4x + 4² - 4 - 12 = 0 </span>
<span>x² + 4x + 16 - 16 = 0 </span>
<span>x² + 4x = 0 <----- Veja que as raízes dessa equação são: x' = 0 e x'' = -4. </span>
<span>Observe que, para m = 4, a equação NÃO se verifica, pois temos uma raiz igual a "0" e a outra negativa (igual a -4). E no enunciado é informado que uma raiz deverá ser nula e a outra positiva. Como deu uma nula e a outra negativa, então m = 4 não convém. </span>

<span>Logo, o valor de "m" deverá ser: </span>

<span>m = -3 <----Pronto. Essa é a resposta. </span>
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