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garik1379 [7]
4 years ago
13

Write a real world problem where you would have to multiply 120 and 75

Mathematics
2 answers:
LekaFEV [45]4 years ago
3 0
I made $120 a week. How much money would I be able to make in 75 weeks?

120 x 75 = 1040

I would make $1040 in 75 weeks. 

Hope this was ok enough. :)
kipiarov [429]4 years ago
3 0
Mike had 75 cupcakes and got 120 more batches how many batches of cupcakes would that be
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(50 POINTS! PLEASE HELP!) Alang has a bag that contains pineapple chews, strawberry chews, and lime chews.
Lelechka [254]

Answer:

<u>1/13</u>

Step-by-step explanation:

Probability (lime chew) :

  • No. of times lime chew was selected / Number of times experiment was conducted
  • 2/26
  • <u>1/13</u>
8 0
2 years ago
Read 2 more answers
For one English test, Mary had to answer 40 questions of these 40 questions, Mary answered 22 of them correctly. What percent di
olga2289 [7]

Answer:

55/100

Step-by-step explanation:

22 of the 40 questions are answered correctly.

To find the percentage I multiply 22/40 by 100/100(it is equal 1)

(22/40)*100/100 = (22*100/40)/100 =55/100

6 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Help math see image for question​
Georgia [21]

Answer:

AAAAAAA!!!!!

Step-by-step explanation:

4 0
3 years ago
(7 + (-3) - 4 ) ÷ ( (-7) x ( 2 - (-6) ) )<br><br> Please show work!
Temka [501]

Answer:

Undefined

Step-by-step explanation:

(7 - 3 - 4) ÷ (-7 * (2+6))

(0) ÷ (-56)

Undefined because zero cannot be divided

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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