<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
Answer:
Step-by-step explanation:
90/100 * x = 15750
0.9 x = 15750
x = 15750/0.9
x = 17500
Now check this by taking 10% off. Do you get 15750?
Let's see
10/100 of 17500 = 1750
Subtract that from 17500
17500 - 1750 = 15750 which is exactly what you should get.
Answer:
False
Step-by-step explanation:
Let p1 be the population proportion for the first population
and p2 be the population proportion for the second population
Then
p1 = p2
p1 ≠ p2
Test statistic can be found usin the equation:
where
- p1 is the sample population proportion for the first population
- p2 is the sample population proportion for the second population
- p is the pool proportion of p1 and p2
- n1 is the sample size of the first population
- n2 is the sample size of the second population.
As |p1-p2| gets smaller, the value of the <em>test statistic</em> gets smaller. Thus the probability of its being extreme gets smaller. This means its p-value gets higher.
As the<em> p-value</em> gets higher, the null hypothesis is less likely be rejected.