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Murljashka [212]
3 years ago
14

Please answer the question from the attachment.

Mathematics
1 answer:
xenn [34]3 years ago
6 0
Change it into improper fraction to make it easier or just solve it as is.
=3\frac{5}{8}-2\frac{7}{8}
=\frac{29}{8}-\frac{23}{8}
=\frac{6}{8}=\frac{3}{4}            
OR
=3 \frac{5}{8}-2 \frac{7}{8}
divide it to two parts:
3-2=1 and \frac{5}{8}-\frac{7}{8}=\frac{-2}{8}
1\frac{-2}{8}⇒(1×8-2=6)
=\frac{6}{8}=\frac{3}{4}
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Find the area of the trapezoid.<br> b1=5<br> b2=7<br> h=4<br><br> PLEASE EXPLAIN TOO!
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Step-by-step explanation:

The formula for finding the area of a trapezoid is\frac{b_{1} + b_{2} }{2} ×h

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Answer:

20 disparos

Step-by-step explanation:

Primera etapa es de determinar cuantos tiros de Camilo acertaron al blanco.

Sabemos que en su última práctica, obtuvo 99 puntos con una mezcla de 5, 8 y 10 puntos.  Eso puedo se exprimir así:

5x + 8y + 10x = 99

Sabemos también que el obtuvo tantos tiros de 8 puntos que de 10 puntos, entonces

y = z

Podemos mezclar las 2 ecuaciones y substituir y por z:

5x + 8y + 10y = 99

5x +18y = 99

Una ecuación, dos variables... no es fácil... pero son números pequeños y se puede intentar soluciones.  Entonces, cuantas veces podemos multiplicar 5 y 18 para obtener 99?

El más simple es de hacer la tabla de multiplicación de 18 y ver cual número nos deja con un multiple de 5.

18 x 1 = 18 (99 - 18 = 81, no un multiple e 5)

18 x 2 = 36 (99 - 36 = 63, no un multiple de 5)

18 x 3 = 54 (99 - 54 = 45, SI, un multiple de 5)

18 x 4 = 72 (99 - 72 = 27, no un multiple de 5)

18 x 5 = 90 (99 - 90 = 9, no un multiple de 5)

Entonces, sabemos que y = 3 y z = 3

5x + 18 (3) = 99

5x + 54 = 99

5x = 45

x = 9

El tiró 9 veces por 5 puntos, 3 veces por 8 puntos y 3 veces pour 10 puntos.

En total tiró 15 veces.

Si acertó 75% (3/4) de las veces, cuantos tiros total?

\frac{15}{3/4} = \frac{15 * 4}{3} = 20

Camilo tiró 20 veces en total.

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