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zvonat [6]
3 years ago
11

If you live in a very cold area, you may have seen the depth of a bank of snow shrink even though temperatures remain below the

melting point of water. How might you account for this observation?
Physics
1 answer:
Aleks04 [339]3 years ago
7 0
<span>To answer the question above, if the day sky is clear it collects radiation. If air is dry snow sublimates faster. If both cases overlap it disappears faster where ever coldest. Thank you for posting your question here. I hope my answer helps. </span>
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A child with a weight of 110 N swings on a playground swing attached to 2.00 m long chains. What is the gravitational potential
Ierofanga [76]

Answer

given,

Weight of the child = 110 N

length of the swing,L = 2 m

now, calculating the potential energy when the string is horizontal

  Potential energy = m g h

 now, h = L (1 - cos θ)   where θ is the angle made by the string with the vertical.

     PE = m g L (1 - cos θ)

   when rope is horizontal θ = 90°

     PE = 110 x 2 (1 - cos 90°)

    PE = 220 J

now, calculating potential energy when string made 25° with horizontal

PE = m g L (1 - cos θ)

   when rope is horizontal θ = 25°

     PE = 110 x 2 (1 - cos 25°)

     PE = 20.61 J

5 0
4 years ago
Assume the average value of the vertical component of Earth's magnetic field is 42 μT (downward) in some region that has an area
Oliga [24]

Answer:

The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

Explanation:

Given that,

Magnetic field = 42 μT

Area A=3.71\times10^{5}\ km^2

A=3.71\times10^{11}\ m^2

We need to calculate the flux per unit area

flux\ per\ unit\ area=\dfrac{42\times10^{-6}}{3.71\times10^{11}}

flux\ per\ unit\ area=1.132\times10^{-16}\ T/m^2

We need to calculate the total earth's surface area

A'=4\pi r^2

A'=4\times\pi\times(6.3781\times10^{6})^2

A'=5.1120\times10^{14}\ m^2

We need to calculate the rest of earth's area

A''=A-A'

Put the value into the formula

A''=5.1120\times10^{14}-3.71\times10^{11}

A''=5.10829\times10^{14}\ m^2

We need to calculate the net magnetic flux through the rest of Earth's surface

B'=5.10829\times10^{14}\times1.132\times10^{-16}

B'=5.782\times10^{-2}\ T

Hence, The net magnetic flux through the rest of Earth's surface is  5.782\times10^{-2}\ T

3 0
4 years ago
A 25.2 kg gazelle moving 2.33 m/s
docker41 [41]
Force = mass x acceleration
113N = 25.2a
a = 4.48 m/s^2
Vf = Vi + at
Vf = 2.33 + 4.48(2) = 11.3 m/s
6 0
3 years ago
A uniform solid sphere rolls down an incline.
SashulF [63]

Answer with Explanation:

We are given that

a.Linear acceleration,a=0.1 g

Moment of inertia of solid sphere,I=\frac{2}{5}mr^2

We know that

a=\frac{gsin\theta}{1+\frac{I}{mr^2}}

Using the formula

0.1g=\frac{gsin\theta}{1+\frac{2mr^2}{5mr^2}}

0.1(1+\frac{2}{5})=sin\theta

sin\theta=0.1\times \frac{7}{5}=0.14

\theta=sin^{-1}(0.14)=8.05^{\circ}

b.When a frictionless block were to slide down the incline at that angle then the motion of block will be linear .There is no rotation.

When the sphere is moving without rotation then, the linear speed of sphere will be larger.

When the linear speed is larger then, the linear acceleration will be larger.

Hence, the magnitude of acceleration will be more.

7 0
4 years ago
Two balls have the same mass. One ball moving along the positive x–axis and the other ball moving along the positive y–axis unde
GalinKa [24]

Answer:

A. The balls stick and move together.

Explanation:

When a bodies undergo perfectly inelastic collision, the two bodies stick together after the collision and begins to move.

In this collision, kinetic energy is not conserved. For perfectly elastic collision, the two bodies conserve kinetic energy and begin to move apart.

Kinetic energy is not conserved because some of the energy gets converted into other forms of energy.

5 0
3 years ago
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