Question

In a certain country, a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of an ounce) has an additional cost. The function below represents the cost of mailing one letter in this country.
f(c)=0.42 + 0.20[x-1]

Josiah has two letters. The first weighs 2.9 ounces, and the second weighs 4.1 ounces. What is the total amount Josiah can expect to pay for postage?
$1.62
$1.64
$1.84

Answer 1

Given:
1st letter : 2.9 ounces
2nd letter: 4.1 ounces

f(1) = 0.42 + 0.20(x-1)
f(1) = 0.42 + 0.20(2.9-1)
f(1) = 0.42 + 0.20(1.9)
f(1) = 0.42 + 0.38
f(1) = 0.80

f(2) = 0.42 + 0.20(4.1-1)
f(2) = 0.42 + 0.20(3.1)
f(2) = 0.42 + 0.62
f(2) = 1.04

0.80 + 1.04 = 1.84 last choice

Answer 2

Answer:

$1.84

Step-by-step explanation:

We are given that a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of an ounce) has an additional cost.

The function which represents the situation:

$f(c)=0.42 + 0.20[x-1]$

Now Joseph has two letters .

The weight of first letter  = 2.9 ounces

Cost of first letter = $0.42 + 0.20[2.9-1]$

                            = $0.8$

Now , second letter  weighs 4.1 ounces

So, cost of second letter = $0.42 + 0.20[4.1-1]$

                                         = $1.04$

Thus the total amount Josiah can expect to pay for postage = $0.8+$1.04

                                                                                                   =$1.84

Hence the total amount Josiah can expect to pay for postage is $1.84