Median: 23.5
12 and 35 are in the middle so you add them and divide by 2, leaving you
23.5 as your median.
Mean: 41.3
Add all numbers together and divide the sum by the number of numbers added. So all numbers added together equals 413. Divide by ten the nuber of numbers added. 413/10 equals 41.3.
Mode: 99
The number that appears most often. In this case, 99 would be the mode.
Range: 98
The lowest number subtracted from the highest number. 99-1 equals 98.
IQR: 84.75
Hope this helped! :)
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The probability of at least three heads can be found by<span><span>∑<span>k=3</span>4</span><span>(<span>4k</span>)</span><span>.5k</span><span>.5<span>4−k</span></span>=<span>516</span></span></span>
(x-3)^2 x=a number in this case
I Think The answer is c I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
