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3 years ago

An experiment consists of flipping a single coin followed by rolling a six-sided cube (a die).

Mathematics

2 answers:

Over [174]3 years ago

8 0

Answer: $\frac{1}{12}$

Step-by-step explanation:

Okay, first, you want to find the probability of getting a head, which would be 1/2 because there are two options and we are only looking for one out of the two. Then, the probability of getting a 6 would be 1/6 because there is only one chance of getting a 6 and there are 6 options. Next, you would have to multiply both quantities to find out what the probability would be of getting both. So it would be $\frac{1}{2}$ × $\frac{1}{6}$ = $\frac{1}{12}$

Reptile [31]3 years ago

5 0

Probability of getting a head followed by a 6 is 1/12

Step-by-step explanation:

There are 2 possible outcomes of tossing a coin a head and a tail.

The probability is 1 out of 2 each for head and tail.

Probability of getting a 6 when a dice is rolled is 1 out of 6 for each face i.e 1,2,3,4,5,6

So the probability of getting a head followed by 6 is 1/2*1/6 = 1/12

It can also be understood as below.

There can be 12 possible combinations once a coin is tossed and a die is rolled. Head-1, Head-2. Head-3, Head-4, Head-5, Head-6, Tail-1, Tail-2, Tail-3, Tail-4, Tail-5, Tail-6

In the list there is 1 outcome that we need. Head-6. This again gives us the chance of getting Head-6 as 1 out of 12.

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3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

Factorise mx+cx+my+cy With steps!!! x=algebra x

avanturin [10]

Step-by-step explanation:

Hey there!

While factorising you remember to make it take common in most of the expression.

Here;

=mx+cx+my+cy

Take common 'x' in "mx+cx" and 'y' in my + cy.

= x(m+c) + y(m+c)

Now, "(m+c)" common again.

= (m+c) (x+y)

Therefore the factorized form of the expression in (m+c)(x+y).

Hope it helps...

6 0

3 years ago

Read 2 more answers

Help plz explain how to use discributive property

DiKsa [7]

1.Identify the fractions. Using the distributive property, you’ll eventually turn them into integers.

2.For all fractions, find the lowest common multiple (LCM) -- the smallest number that both denominators can fit neatly into. This will allow you to add fractions.

3.Multiply every term in the equation by the LCM.

4.Isolate variables adding or subtracting like terms on both sides of the equals sign.

5.Combine like terms.

6.Solve the equation and simplify, if needed.

5 0

3 years ago

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What is the length of c in inches

crimeas [40]

Answer:

$\sqrt{500}$ inches

Step-by-step explanation:

a^2+b^2=c^2

10^2+20^2=c^2

100+400=c^2

c^2=500

$\sqrt{500}$

4 0

3 years ago

Can somebody please clearly (and correctly) explain how to successfully work out this question?

STatiana [176]

Answer:

Step-by-step explanation:

To calculate the number of tiles needed

divide 4m by 0.2m for row of tiles ⇒ 20 tiles per row

divide 3m by 0.2m for column of tiles ⇒ 15 tiles per column

number of tiles = 20 × 15 = 300

number of packs = 300 ÷ 10 = 30

cost = 30 × £34.99 = £1049.70

Since she has £1000 to spend and £1049.70 > £1000

She does not have enough to cover the wall

6 0

3 years ago