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notsponge [240]
3 years ago
13

An experiment consists of flipping a single coin followed by rolling a six-sided cube (a die).

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:\frac{1}{12}

Step-by-step explanation:

Okay, first, you want to find the probability of getting a head, which would be 1/2 because there are two options and we are only looking for one out of the two. Then, the probability of getting a 6 would be 1/6 because there is only one chance of getting a 6 and there are 6 options. Next, you would have to multiply both quantities to find out what the probability would be of getting both. So it would be \frac{1}{2} ×\frac{1}{6}=\frac{1}{12}

Reptile [31]3 years ago
5 0

Probability of getting a head followed by a 6 is 1/12

Step-by-step explanation:

There are 2 possible outcomes of tossing a coin a head and a tail.

The probability is 1 out of 2 each for head and tail.

Probability of getting a 6 when a dice is rolled is 1 out of 6 for each face i.e 1,2,3,4,5,6

So the probability of getting a head followed by 6 is 1/2*1/6 = 1/12

It can also be understood as below.

There can be 12 possible combinations once a coin is tossed and a die is rolled. Head-1, Head-2. Head-3, Head-4, Head-5, Head-6, Tail-1, Tail-2, Tail-3, Tail-4, Tail-5, Tail-6

In the list there is 1 outcome that we need. Head-6. This again gives us the chance of getting Head-6 as 1 out of 12.

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Step-by-step explanation:

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3 years ago
A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
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Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

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3 years ago
Answer sooon pls i will give thebrainliest for the correct answer☺
OleMash [197]
The correct answer is 5
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Dmitriy789 [7]
.000000054 is the answer
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