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Eva8 [605]
3 years ago
14

The pre-image, ΔSTU, has undergone a type of transformation called a rigid transformation to produce the image, ΔVWX. Compare th

e measures of the triangles by dragging the image to the pre-image.
Which measures are equal? Check all that apply.

ST = VW
SU = VX
TU = WX
m∠SUT = m∠VXW
m∠TSU = m∠WVX
m∠UTS = m∠XWV
Mathematics
1 answer:
maw [93]3 years ago
5 0

Answer:

all of them

Step-by-step explanation:

yuh yuh

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Sliva [168]

Answer:

Simply subtract the fail rate from 100; the resulting number is the pass rate. So, if you know that 6 percent of students failed, you would subtract: 100 - 6 = 94 percent is the pass rate for the test.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Sammy is trying to determine how many triangles she can create out of a square grid that has a side of 10 inches. Use the image
Oksanka [162]
I think the answer is C. (a.k.a the third one)
I hoped this helped !!
3 0
3 years ago
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State whether the graph would be a circle, ellipse, parabola, or hyperbola.
Lubov Fominskaja [6]

Answer:

ellipse

Step-by-step explanation:

bc you should already know

7 0
3 years ago
Sam received $125 for his birthday. He spent $85 at the store and put the rest in the
anastassius [24]

Answer:

68%

Hope it helps

5 0
3 years ago
Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
motikmotik

Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

3 0
3 years ago
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