Question

Find the roots.1) f(x) = - x^2 + 6x + 272) f(x) = 3x^2 + 17x - 20​

Answer 1

Answer:

1)  x1=-3 and x2=9

2) x1=-20/3 and x2=1

Step-by-step explanation:

We can use the quadratic equation to solve every problem related with quadratic term, that is a equation written as ax^2 + bx +c =0

$x=\frac{-b+/- \sqrt{b^{2}-4ac } }{2a}$

Remember that the +/- sign means that there are two solutions, one using the + sign and other usign the - sign.

For the first polynomial we have a=-1, b = 6, c=27

Using the quadratic equation we have> x1=-3 and x2=9.

For the second polynomial we have a=3, b=17, c=-20.

Using the quadratic equation we have> x1=-20/3 and x2=1.