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Fed [463]
3 years ago
5

uka and Anja each measured the height of their friend three times. Their friend is 59 inches tall. They recorded their measureme

nts as shown. Luka: 59 in., 58, in., 58 in. Anja: 59.3 in., 59.6 in., 58.2 in. Which statement is true? Luka’s measurements are more precise and more accurate. Anja’s measurements are more precise and more accurate. Luka’s measurements are more precise, but Anja’s measurements are more accurate. Luka’s measurements are more accurate, but Anja’s measurements are more precise.
Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0
<span>Luka’s measurements are more precise, but Anja’s measurements are more accurate is the answer . because luka rounded the answer while anja is giving you the true value her answers are going to be more accurate cheers </span>
Rom4ik [11]3 years ago
4 0
Hello there!

Your correct answer would be the (last option, option d). The reason to why L<span>uka’s measurements are more accurate, but Anja’s measurements are more precise would be because if you have noticed, Luka's is rounded to the answer, which would make this accurate, because it's rounded. But when it is very precise, that would be different, because this would not be accurate, because it would contain a direct number in this situation.

I hope this helps you!</span>
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faltersainse [42]

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Step 2 of 2

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\begin{array}{c}\\\left( \begin{array}{l}\\{\rm{Positive Predictive }}\\\\{\rm{value}}\left( {PPV} \right)\\\end{array} \right) = \frac{{{\rm{Prevalence}} \times {\rm{Sensitivity}}}}{{\left( {{\rm{Prevalence}} \times {\rm{Sensitivity}}} \right) + \left( {{\rm{1 - Prevalence}} \times 1 - {\rm{Specificity}}} \right)}}\\\\ = \frac{{0.1 \times 0.60}}{{\left( {0.1 \times 0.60} \right) + \left( {1 - 0.1 \times 1 - 0.70} \right)}}\\\\ = \frac{{0.06}}{{0.33}}\\\\ = 0.181818\\\\ = 0.182{\rm{ }}\left( {{\rm{Round to 3 decimal place}}} \right)\\\end{array}  

(Positive Predictive  value, PPV) =

(Prevalence×Sensitivity)/Prevalence×Sensitivity +(1−Prevalence×1−Specificity)  

=   (0.1×0.60)/0.1×0.60  + (1−0.1×1−0.70) ​  

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=   0.181818

(Positive Predictive  value, PPV) = 0.182 (3decimals)    

We have to convert the PPV into percentage,

\begin{array}{c}\\PPV = 0.182 \times 100\\\\ = 18.2\% \\\end{array}  

PPV=0.182×100

= 18.2% ​  

Therefore, the predictive positive value is 18.2%.

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