What is the quotient of 6 and -1/2? <br> A. -12<br> B. -1/2<br> C.1/12<br> D. 12

Please help with this question!!!

marin [14]

Answer:

length: 12 ft

area: 72 square feet

Step-by-step explanation:

Let L represent the length of the mat in feet. Then L/2 is the width and the perimeter is ...

P = 36 = 2(L +L/2) = 3L . . . . . substitute the given information and simplify

12 = L . . . . . . divide by 3

The length of the mat is 12 ft.

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The width of the mat is L/2 = 6 ft, and the area is the product of length and width.

Area = (12 ft)(6 ft) = 72 ft^2

The area of the mat is 72 square feet.

7 0

3 years ago

To avoid a storm, a passenger-jet pilot descended 0.44 mile in 0.8 minutes. What was the planes average change of altitude per m

Tcecarenko [31]

The average change of altitude per minute would simply be the ratio of distance descended over time. That is:

average change of altitude = distance / time

average change of altitude = 0.44 mile / 0.8 minutes

<span>average change of altitude = 0.55 mile / minute</span>

6 0

2 years ago

Find the surface area of the composite solid.

natulia [17]

Answer:

Step-by-step explanation:

$440.4 + 5\cdot(\frac12\cdot16\cdot20)=440.4+800=1240.4\ mm^2$

4 0

3 years ago

A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates

KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

$P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}$ (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0

2 years ago

Mary took 8 tests in science and received the following scores: 87,60,76,92,63,91,88,75

MariettaO [177]

Answers:

mean = 79
mode = none
median = 81.5

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Explanation:

To get the mean, you add up the numbers and then divide by n = 8, since there are 8 scores

Adding the scores gets us: 87+60+76+92+63+91+88+75 = 632

Divide that over n = 8 to get 632/n = 632/8 = 79

The mean is 79

You have the correct answer. Nice work.

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The mode is the most frequent value.

In this data set, we don't have any repeated values. Each unique number is listed one time only. So that tells us we don't have a mode here.

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To get the median, we need to sort the items from smallest to largest

{87,60,76,92,63,91,88,75} sorts to {60,63,75,76,87,88,91,92}

Because we have n = 8 values, which is an even number, this tells us that the median is between slot n/2 = 8/2 = 4 and slot 5

The values 76,87 are in slots four and five in that order. Add them up and divide by 2: (76+87)/2 = 163/2 = 81.5 is the median

3 0

3 years ago

What is the quotient of 6 and -1/2? A. -12 B. -1/2 C.1/12 D. 12