Answer:
μ ≈ 2.33
σ ≈ 1.25
Step-by-step explanation:
Each person has equal probability of ⅓.
The mean is the expected value:
μ = E(X) = ∑ X P(X)
μ = (1) (⅓) + (2) (⅓) + (4) (⅓)
μ = ⁷/₃
The standard deviation is:
σ² = ∑ (X−μ)² P(X)
σ² = (1 − ⁷/₃)² (⅓) + (2 − ⁷/₃)² (⅓) + (4 − ⁷/₃)² (⅓)
σ² = ¹⁴/₉
σ ≈ 1.25
We have that
y< 6x-3
using a graph tool
see the attached figure
the answer in the attached figure
Answer: 0.0035
Step-by-step explanation:
Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
i.e. and
Let x denotes the readings on thermometers.
Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_
Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035
The required region is attached below .
Answer:
A
Step-by-step explanation: