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Eddi Din [679]
3 years ago
11

Did chimps feed more on seeds or leaves during May?

Chemistry
1 answer:
Naya [18.7K]3 years ago
6 0
Chimps feed on seeds more
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What are the elements of scientific method?​
Digiron [165]

Answer:

The basic steps of the scientific method are: 1) make an observation that describes a problem, 2) create a hypothesis, 3) test the hypothesis, and 4) draw conclusions and refine the hypothesis.

7 0
3 years ago
Malonic acid, h2c3h2o4, is a diprotic acid with ka1= 1.5 x 10-3and ka2= 2.0 x 10-6. what is the concentration of the malonate an
Bess [88]

In a 0.15 m solution of malonic acid, the amount of the malonate anion, c3h2o42-, is 1.68*10^{-4} M.

Explanation:

For the first equlibria;

initial concentration of H_{2}C_{3}H_{2}OH=0.15

initial concentration of HC_{3}H_{2}O_{4}^{-} =0

initial concentration of H^{+} =0

Let concentration change of H_{2}C_{3}H_{2}OH=-x

Let concentration change of HC_{3}H_{2}O_{4}^{-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  H_{2}C_{3}H_{2}OH=0.15-x

Let concentration in equilibrium state ofHC_{3}H_{2}O_{4}^{-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{1}=\frac{x*x}{0.15-x}=\frac{1.5*10^{-3}}{1} =\frac{x^{2}}{0.15-x}

x^{2}+0.0015x-0.000225=0

Which is a quadratic equation in x, solving it gives;

x=0.01427

Therefore, HC_{3}H_{2}O_{4}^{-} =x= 0.01427M

Now for the second equlibria;

initial concentration of HC_{3}H_{2}O_{4}^{-}=0.01427

initial concentration of C_{3}H_{2}O_{4}^{2-} =0

initial concentration of H^{+} =0

Let concentration change of HC_{3}H_{2}O_{4}^{-}=-x

Let concentration change of  C_{3}H_{2}O_{4}^{2-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  HC_{3}H_{2}O_{4}^{-}=0.01427-x

Let concentration in equilibrium state ofC_{3}H_{2}O_{4}^{2-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{2}=\frac{x*x}{0.01427-x}=\frac{2.0*10^{-6}}{1} =\frac{x^{2}}{0.01427-x}

2.854*10^{-8}-(2.0*10^{-6})x=x^{2}

Therefore, C_{3}H_{2}O_{4}^{2-} =x= 1.68*10^{-4}M

<h3>What is a malonic acid?</h3>

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. For instance, the diethyl ester of malonic acid is called diethyl malonate.

Polyester and polymers both employ malonic acid as a precursor. Both the scent business and the flavoring sector utilize it. It is employed to regulate acidity. Malonic acid contributes to the production of fatty acids in people. Malonic acid has been found in a number of foods outside of the human body, including red beets, corn, scarlet beans, common beets, and cow milks, although its presence has not been defined. The group of organic substances known as dicarboxylic acids and derivatives includes malonic acid, also known as malonate or H2MALO.

To know more about malonic acid, visit:

brainly.com/question/13943912?referrer=searchResults

#SPJ4

4 0
1 year ago
Decribe an example of how external temperature may affect human body functions
marusya05 [52]
If your body temperature falls to 95°F (35°C) or lower, you have “hypothermia.” This condition can potentially lead to cardiac arrest, brain damage, or even death. If your body temperature rises as high as 107.6°F (42 °C), you can suffer brain damage or even death.
4 0
3 years ago
What is the maximum amount of water (in grams) that can be removed from 15ml of toluene by the addition?
Nataly [62]

Complete Question

Magnesium sulfate forms a hydrate with the formula MgSO_4. 7H_20. What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of MgSO_4 is 120.4 g/mol; H20 = 18 g/mol.

Answer:

The value  is  z =  0.2093 \  g of  H_2O

Explanation:

From the question we are told that

   The volume of toluene is  V = 15 mL

    The mass of  anhydrous magnesium sulfate is  m =  200m g  = 200 *10^{-3} \  g

   The formula of the hydrate is   MgSO_4. 7H_20

    The molar mass of   MgSO_4  is  z =120.4 \ g/mol

From the formula given we see that

  1 mole of  Mg SO_4 wil remove  7 moles of H_2O to for the given formula

Hence

  120.4 g (1 mole) will remove  7 moles (7 * 18 g = 126 g  ) of  H_2O to for the given formula

Therefore 1 g of  Mg SO_4  x g  of  H_2O  

So

     x  =  \frac{x]126 *  1}{ 120.4 }

=>     x  =  1.0465 \  g

From our calculation we obtained that

  1 g of Mg SO_4 will remove  x  =  1.0465 \  g  of  H_2O  

Then  

   200 *10^{-3} \  g of Mg SO_4 will remove z g of  x  =  1.0465 \  g  of  H_2O  

So

   z =  200 *10^{-3} *  1.0465

=>z =  200 *10^{-3} *  1.0465

=>z =  0.2093 \  g of  H_2O  

6 0
3 years ago
Convert 23 calories into kcal​
AVprozaik [17]

0.023, to do it, just simply divide the energy value by 1000.

6 0
3 years ago
Read 2 more answers
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