Explanation:
Non-metals are the species that are electron deficient and they are able to accept one or more electrons from a donor atom in order to complete their octet.
For example, carbon (C), nitrogen (N), chlorine, (Cl), phosphorus (P) etc are all non-metals.
Metals are the species that contain more number of electrons in their valence shell and in order to attain stability they easily lose an electron.
For example, sodium (Na), lithium (Li), Beryllium (Be), Magnesium (Mg) etc are all metals.
Metalloids are the species that show properties of both metals and non-metals.
For example, Boron (B), Antimony (Sb), Silicon (Si) and Germanium (Ge) etc are metalloids.
Explanation:
Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.
Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.
No. of moles = 
= 
= 0.2 mol
Molarity of acetic acid is calculated as follows.
Density = 
1 g/ml = 
volume = 100 ml
Hence, molarity = 
= 
= 2 mol/l
As reaction equation for the given reaction is as follows.
So, moles of NaOH = moles of acetic acid
Let us suppose that moles of NaOH are "x".
(as 1 L = 1000 ml)
x = 20 L
Thus, we can conclude that volume of NaOH required is 20 ml.
Answer: Hmmmmm that's crazy....
There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.
Fraction remaining (FR) = 0.5n
n = number of half lives that have elapsed
In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).
0.0156 = 0.5n
log 0.0156 = n log 0.5
-1.81 = -0.301 n
n = 6.0 half lives have elapsed
Explanation:
Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)
This sounds good so far.
May want to check how you say "and are spread way out" - a better way to say it would be "the crystals are spread out"
A solution that appears dark orange in color is not absorbing all orange wavelengths of light.
