Question

Estimate the average force exerted by a shot-putter on a 7.0-kg shot if the shot is moved through a distance of 2.8 m and is released with a speed of 13 m/s

Answer 1

Velocity (speed) x gravity = acceleration

13ms^-1 x 10ms^-2 = 130ms^-2

Force = mass x acceleration

Force = 7kg x 130ms^-2

Force = 910 Newtons.

I'm not 100% sure if this is correct but without the assurance of a teacher, this is how I would go about this question :) hope this helped!

Answer 2

Answer:

The force is 211.19 N.

Explanation:

Given that,

Mass = 7.0 kg

Distance = 2.8 m

Speed = 13 m/s

We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

Put the value in the equation

$13^2=0+2\times a\times2.8$

$a=\dfrac{13^2}{2\times2.8}$

$a=30.17\ m/s^2$

We need to calculate the force

Using newton's second law

$F = ma$

Put the value into the formula

$F = 7.0\times30.17$

$F = 211.19\ N$

Hence, The force is 211.19 N.