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3 years ago

How many grams of ammonium chloride is soluble at 50 C

Physics

1 answer:

user100 [1]3 years ago

5 0

Ammonium chloride is soluble at 80g.

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Carey and Marcy are performing a lab to determine the speed of sound in air with the apparatus that was demonstrated in the vide

andre [41]

Answer:

the frequency is the fundamental and distance is L = ¼ λ

Explanation:

This problem is a phenomenon of resonance between the frequency of the tuning fork and the tube with one end open and the other end closed, in this case at the closed end you have a node and the open end a belly, so the wavelength is the basis is

λ = 4 L

In this case L = 19.4 cm = 0.194 m

let's use the relationship between wave speed and wavelength frequency and

v = λ f

where the frequency is f = 440 Hz

v = 4 L f

let's calculate

v = 4 0.194 440

v = 341.44 m / s

so the frequency is the fundamental and distance is

L = ¼ λ

5 0

4 years ago

A particle travels along the curve from A to B in 5 s. It takes 8 s for it to go from B to C and then 10 s to go from C to A. De

Elza [17]

Answer:

5.1 m/s

Explanation:

The figure is missing: find it in attachment.

In order to find the average speed, we have to calculate the length of the total path, and divide it by the total time elapsed.

The curve from A to B is a quarter of a circle with a radius of r = 20 m, so its length is:

$AB=\frac{\pi r}{2}=\frac{\pi (20)}{2}=31.4 m$

The path BC is the hypothenuse of a right triangle with sides equal to 20 m and 30 m, so its length is

$BC=\sqrt{30^2+20^2}=36 m$

Finally, the length of the path AC is the sum of the side of 30 m and the radius of the curve, so

$AC=30 + 20 = 50 m$

So the total distance covered is

$d=AB+BC+AC=31.4+36+50=117.4 m$

The total time elapsed is

$t=5 s + 8 s + 10 s =23 s$

So, the average speed is

$v=\frac{d}{t}=\frac{117.4}{23}=5.1 m/s$

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3 years ago

In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres o

SVETLANKA909090 [29]

Answer:

$F = 7.7*10^{-10}N$

Explanation:

You need to be careful with units for this problem. The force will be:

$F =\frac{K*m1*m2}{d^2}$

$F=\frac{6.67259 * 10^{-11}*1.56*21.1*10^{-3}}{(5.34*10^{-2})^2}$

$F=7.7*10^{-10}N$

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3 years ago

What is the momentum of a 1200 kg car traveling with a speed of 27 m/s (60 mph)?

serious [3.7K]

Answer:

This is your answer

Explanation:

Actually I took this from go ogle

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3 years ago

PLEASE HELP ME

son4ous [18]

Answer:

synthesis is correct answer.

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3 years ago