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frutty [35]
3 years ago
5

Red light strikes a metal surface and electrons are ejected. If violet light is now used with a 10% greater intensity, what will

happen to the ejection rate (number of ejected electrons per second) and the maximum energy of the electrons?A) greater ejection rate; same maximum energyB) same ejection rate; greater maximum energyC) greater ejection rate; greater maximum energyD) same ejection rate; same maximum energyE) none of the above answers are correct
Physics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

correct answer is C

Explanation:

The photoelectric effect was correctly described by Einstein, where he assumes that the light ray is formed by photons that are articulated and behaves like an elastic shock, the energy of this particular is described by the Planck equation.

             K = h f + Ф

where k is the kinetic energy of the electrons, f the frequency of the photons and Ф the work function of the material.

In this experiment, red light removes electrons, it is assumed that each photon spreads an electron if we have another light with more energy and 10% more intense, that is, with 10% more shapes and each arcane an electron the number of electrons removed of; material is increased by 10%.

The change in wavelength and consequently the frequency

            c = λ f

            f = c /λ

therefore, the wavelength of the voilet λ = 400 num has a higher frequency and therefore more energy, so that the turned-on turns have more kinetic energy.

With these approaches we examine the final answers where the correct answer is C

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Answer:

The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

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Given that,

Diameter = 2.62 mm

Frequency = 2.15 GHz

(A). We need to calculate the magnetic field strength

Using formula of the magnetic field strength

B=\dfrac{2\pi mf}{e}

Where, f = frequency

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Put the value into the formula

B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}

B=0.077\ T

(B). We need to calculate the energy of electron

Using formula of energy

E=\dfrac{1}{2}m(r\omega)^2

E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2

E=1.4249\times10^{-16}\ J

The energy in eV

1 eV=1.6\times10^{-16}\ J

E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}

E=0.8906\ eV

Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

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An object 2.2 kg object accelerates at 4.0 m/s^2. What is the mass of the object?
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