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frutty [35]
3 years ago
5

Red light strikes a metal surface and electrons are ejected. If violet light is now used with a 10% greater intensity, what will

happen to the ejection rate (number of ejected electrons per second) and the maximum energy of the electrons?A) greater ejection rate; same maximum energyB) same ejection rate; greater maximum energyC) greater ejection rate; greater maximum energyD) same ejection rate; same maximum energyE) none of the above answers are correct
Physics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

correct answer is C

Explanation:

The photoelectric effect was correctly described by Einstein, where he assumes that the light ray is formed by photons that are articulated and behaves like an elastic shock, the energy of this particular is described by the Planck equation.

             K = h f + Ф

where k is the kinetic energy of the electrons, f the frequency of the photons and Ф the work function of the material.

In this experiment, red light removes electrons, it is assumed that each photon spreads an electron if we have another light with more energy and 10% more intense, that is, with 10% more shapes and each arcane an electron the number of electrons removed of; material is increased by 10%.

The change in wavelength and consequently the frequency

            c = λ f

            f = c /λ

therefore, the wavelength of the voilet λ = 400 num has a higher frequency and therefore more energy, so that the turned-on turns have more kinetic energy.

With these approaches we examine the final answers where the correct answer is C

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Increase the mass of the beanbag its gravitational potential energy will
kotegsom [21]

The gravitational potential energy will increase

Explanation:

The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in a gravitational field.

Near the Earth's surface, the GPE of an object is given by

GPE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object above the ground

From the equation, we see that the GPE is directly proportional to the mass: therefore, if the mass increases, the GPE will increase as well.

So, for the beanbag in this problem, when its mass increases, the GPE will increase as well.

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5 0
2 years ago
If the voltage across the first capacitor (the one with capacitance
RoseWind [281]
The answer to this question is: it depends. It depends on the arrangement of the capacitors in a circuit: it can be either in series or in parallel. The difference is shown in the picture. 

Capacitors are like batteries in a way that they store power from the source. It has some rules depending on the type of circuit. For parallel circuits, the voltage across each capacitor is equal. Therefore, V₁=V₂=V₃.

On the other hand, if the capacitors are arranged in series, the voltage across each capacitor should add up to the total voltage of the source. Therefore, V₁+V₂+V₃ = Total Voltage.


8 0
3 years ago
The 20-g bullet is travelling at 400 m/s when it becomes embedded in the 2-kg stationary block. The coefficient of kinetic frict
nikklg [1K]

Answer:

The distance the block will slide before it stops is 3.3343 m

Explanation:

Given;

mass of bullet, m₁ = 20-g = 0.02 kg

speed of the bullet, u₁ =  400 m/s

mass of block, m₂ = 2-kg

coefficient of kinetic friction,  μk = 0.24

Step 1:

Determine the speed of the bullet-block system:

From the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

v is the speed of the bullet-block system after collision

(0.02 x 400) + (2 x 0) = v (0.02 + 2)

8 = v (2.02)

v = 8/2.02

v = 3.9604 m/s

Step 2:

Determine the time required for the bullet-block system to stop

Apply the principle of conservation momentum of the system

v(m_1+m_2) -F_kt = v_f(m_1 +m_2)\\\\v(m_1+m_2) -N \mu_kt = v_f(m_1 +m_2)\\\\v(m_1+m_2) -g(m_1 +m_2) \mu_kt = v_f(m_1 +m_2)\\\\3.9604(2.02)-9.8(2.02)0.24t = v_f(2.02)\\\\8 - 4.751t = 2.02v_f\\\\3.9604 - 2.352t = v_f

when the system stops, vf = 0

3.9604 -2.352t = 0

2.352t = 3.9604

t = 3.9604/2.352

t = 1.684 s

Thus, time required for the system to stop is 1.684 s

Finally, determine the distance the block will slide before it stops

From kinematic, distance is the product of speed and time

S = \int\limits {v} \, dt \\\\S = \int\limits^t_0 {(3.9604-2.352t)} \, dt\\\\ S = 3.9604t - 1.176t^2

Now, recall that t = 1.684 s

S = 3.9604(1.684) - 1.176(1.684)²

S = 6.6693 - 3.3350

S = 3.3343 m

Thus, the distance the block will slide before it stops is 3.3343 m

3 0
3 years ago
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Gnom [1K]

Answer:

<em>-z axis</em>

Explanation:

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An empty 230 kg elevator accelerates upward
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Answer:

7.2 as used in the equation

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3 years ago
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