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frutty [35]
3 years ago
5

Red light strikes a metal surface and electrons are ejected. If violet light is now used with a 10% greater intensity, what will

happen to the ejection rate (number of ejected electrons per second) and the maximum energy of the electrons?A) greater ejection rate; same maximum energyB) same ejection rate; greater maximum energyC) greater ejection rate; greater maximum energyD) same ejection rate; same maximum energyE) none of the above answers are correct
Physics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

correct answer is C

Explanation:

The photoelectric effect was correctly described by Einstein, where he assumes that the light ray is formed by photons that are articulated and behaves like an elastic shock, the energy of this particular is described by the Planck equation.

             K = h f + Ф

where k is the kinetic energy of the electrons, f the frequency of the photons and Ф the work function of the material.

In this experiment, red light removes electrons, it is assumed that each photon spreads an electron if we have another light with more energy and 10% more intense, that is, with 10% more shapes and each arcane an electron the number of electrons removed of; material is increased by 10%.

The change in wavelength and consequently the frequency

            c = λ f

            f = c /λ

therefore, the wavelength of the voilet λ = 400 num has a higher frequency and therefore more energy, so that the turned-on turns have more kinetic energy.

With these approaches we examine the final answers where the correct answer is C

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3 years ago
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The minimum stopping distance of a car moving at 20.5 mi/h is 11.6 m. Under the same conditions (so that the maximum braking for
pshichka [43]

Answer:

d = 69 .57 meter

Explanation:

First case

Speed of car ( v )  = 20.5 mi/h  = 9.164  M/S

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Work done = 0.5 m v²  = 0.5 * 9.164² * m J  = 41.99 m J

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Second case

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d = ?

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Since the braking force remains the same .

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3 years ago
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A​ DC-9 aircraft leaves an airport from a runway whose bearing is N4343degrees°E. After flying for one half 1 2 ​mile, the pilot
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Explanation:

The direction N43°E is perpendicular to the direction south-east when the plane turn 90° and heads in the south-east direction.

Since the distance 1/2 mile N43°E is perpendicular to the distance 1 mile south-east, we have a right angled triangle.

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So, our bearing is 103.4° or S76.6°E

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4 years ago
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