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IgorC [24]
4 years ago
7

Describe one way that the student can determine the exact volume of one of the three blocks

Physics
1 answer:
Vinil7 [7]4 years ago
7 0

Density is defined as an object's mass per a given unit of volume. So, if you know the object's density, and you're able to weigh it, you can determine its volume with the equation:


Volume = weight / density


<em>There is a link in the Resources section to a web page which lists the densities of some common materials. Note that density changes with pressure or temperature</em>.

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An object moves with constant acceleration 4.00 m/s^2 and over a time interval reaches a final velocity of 12.0 m/s.
Bas_tet [7]
A) We can use the equation of motion:
2as = v² - u²
s = (12² - (-6)²) / 2 x 4
s = 13.5 m

b) We calculate the time over which this displacement occurred using:
v = u + at
t = (12 - -6)/4
t = 4.5 seconds
Assuming the average speed equal to:
(12 + 6) /2 = 9 m/s
average speed = total distance/total time
total distance = 9 x 4.5
= 40.5 m
7 0
3 years ago
In what direction must you pull on the third rope to keep the knot from moving?
Thepotemich [5.8K]
What are the answers?
3 0
3 years ago
What acceleration would you expect a 100 kg individual to experience from a 1000N force?
german

Answer: 10 m/2^2

F=ma

Explanation:

Force = 1000N

1 N is 1 (kg*m/s^2)

Mass = 100kg

F=ma

a = F/m

a = (1000kg*m/s^20/(100kg)

a = 10 m/s^2

7 0
3 years ago
17. A 120 m long train is moving in a direction with speed 20 m/s. A train B moving with 30
nydimaria [60]
Answer is D.

Speed:
Use relative speed to simplify the situation. Since the trains are moving in opposite directions, you can add the speeds and pretend the first train is stationary (moving at 0m/s) and the second train is moving at 50m/s.

Distance:
The front of the second train needs to travel 120m to get from the front to the back of the first train. When the front of the second train is at the back of the first train, the back of the second train is still 10m in front of the first train. The back therefore has to travel 130m to clear the first train. The total distance over which the trains are overlapping in this scenario is therefore 120 + 130 = 250m.

You have speed and you have distance so now just calculate time:

v = d / t
50 = 250 / t
t = 5s
4 0
3 years ago
a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the
erma4kov [3.2K]

The emerging velocity of the bullet is <u>71 m/s.</u>

The bullet of mass <em>m</em> moving with a velocity <em>u</em>  has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed <em>v</em> when it emerges from the block.

If the block exerts a resistive force <em>F</em> on the bullet and the thickness of the block is <em>x</em> then, the work done by the resistive force is given by,

W=Fx

This is equal to the change in the bullet's kinetic energy.

W=Fx=\frac{1}{2} m(u^2-v^2)......(1)

If the thickness of the block is reduced by one-half, the bullet emerges out with a velocity v<em>₁.</em>

Assuming the same resistive forces to act on the bullet,

F(\frac{x}{2} )=\frac{1}{2} m(u^2-v_1^2)......(2)

Divide equation (2) by equation (1) and simplify for v<em>₁.</em>

\frac{\frac{Fx}{2} }{Fx} =\frac{(u^2-v_1^2)}{(u^2-v^2)} \\\frac{100^2-v_1^2}{100^2-10^2} =\frac{1}{2} \\v_1^2=5050\\v_1=71.06 m/s

Thus the speed of the bullet is 71 m/s


3 0
3 years ago
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