Circle the equation with roots 4 and -8

1 answer:

4 0

Wih roots r1 and r2
the factors are (x-r1)(x-r2)

roots 4 and -8
(x-4)(x-(-8))
(x-4)(x+8)
x^2+4x-32 is the equation

either (x-4)(x+8) or x^2+4x-32

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The final position of the surveyor is represented by the following vectorial sum:

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$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: