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3 years ago

Which of the following is polynomial?

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

Answer:

$x^2-1$ has two terms without any negative exponent. so it is a polynomial.

Step-by-step explanation:

A polynomial is a expression with more than one terms.

The expression with negative exponent is not a polynomial.

Expression in the denominator is also not a polynomial

$x^2-1$ has two terms without any negative exponent. so it is a polynomial.

option B,C and D has negative exponents, so it is not a polynomial.

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Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can

brilliants [131]

Using the formula given: d = √(3h/2)

We simply substitute the given values of h into the equation and compare the results.

For Wyatt where h = 120:
d = √(3(120)/2)
d = 13.42 miles

For Shawn where h = 270:
d = √(3(270)/2)
d = 20.12 miles

Since the question asks for how much farther can Shawn see, we subtract the results:

20.12 - 13.42 = 6.7

Therefore, Shawn can see 6.7 miles farther.

4 0

3 years ago

Solve the system of equations using a matrix X+3y=5 X+4y=6

shusha [124]

Answer:

x=2 and y=1

Step-by-step explanation:

if y is 1 then u can multiply the three and 4 which is the same and then add 2 which add up to 5 and 6

7 0

3 years ago

Dovator [93]

Answer:

Step-by-step explanation:

5 0

3 years ago

Pls help with this question I give brainliest thank uuuuu!

Snezhnost [94]

Answer:

B. 88.5

Step-by-step explanation:

first we add all the numbers :

(79 +80 +92 +92 +81 +100 +88 +98 +71 + 100+91+90) over 12

= 1062 over 12

= 88.5

[why over 12? because there's 12 numbers]

8 0

3 years ago

These two trapezoids are similar What is the correct way to complete the similarity statement?

pentagon [3]

Option A:

$\mathrm{ABCD} \sim \mathrm{GFHE}$

Solution:

ABCD and EGFH are two trapezoids.

To determine the correct way to tell the two trapezoids are similar.

Option A: $\mathrm{ABCD} \sim \mathrm{GFHE}$

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, $\mathrm{ABCD} \sim \mathrm{GFHE}$ is the correct way to complete the statement.

Option B: $\mathrm{ABCD} \sim \mathrm{EGFH}$

In the given image length of AB ≠ EG.

So, $\mathrm{ABCD} \sim \mathrm{EGFH}$ is the not the correct way to complete the statement.

Option C: $\mathrm{ABCD} \sim \mathrm{FHEG}$

In the given image length of AB ≠ FH.

So, $\mathrm{ABCD} \sim \mathrm{FHEG}$ is the not the correct way to complete the statement.

Option D: $\mathrm{ABCD} \sim \mathrm{HEGF}$

In the given image length of AB ≠ HE.

So, $\mathrm{ABCD} \sim \mathrm{HEGF}$ is the not the correct way to complete the statement.

Hence, $\mathrm{ABCD} \sim \mathrm{GFHE}$ is the correct way to complete the statement.

3 0

3 years ago