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mixer [17]
3 years ago
8

There are two pendulums with periods 1.5 s and 1 s, which one is longer, and which one is shorter.

Physics
1 answer:
Stells [14]3 years ago
3 0

Answer:

The greater the length, the greater the period. Or vice versa

Explanation:

T = 2π * √(L/g)

Given that T = 1s , g = 9.8m/s^2 , π = 3.14

1 = 2× 3.14 √(L/9.8)

1 = 6.28 ×L /9.8

L= 9.8/6.28

L= 1.56m

When T = 1.5s

1.5 = 2×3.14√(L/9.8)

1.5^2 = 6.28×L/9.8

2.25 = 6.28L/9.8

2.25×9.8 = 6.28L

22.05 = 6.28L

L = 22.05/6.28

L = 3.51m

From the above mathematical solution, it is clear that the greater the length, the greater the period. Or vice versa

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3) A driver in a 1000-kg car traveling at 24 m/s slams on the brakes and skids to a stop. If the coefticient of friction between
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A) 37 m

Explanation:

The car is moving of uniformly accelerated motion, so the distance it covers can be calculated by using the following SUVAT equation:

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a is the acceleration

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We need to find the acceleration first. We know that the force responsible for the (de)celeration is the force of friction, so:

F=ma=-\mu mg

where

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a is the deceleration of the car

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And we can substitute it into eq.(1) to find d:

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