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ivann1987 [24]
3 years ago
10

Cars A and B are racing each other along the same straight road in the following manner:

Physics
1 answer:
zysi [14]3 years ago
8 0

Answer:

\frac{x_{o}}{v_B-V_A} =t

Explanation:

Represent the car's position as a function

x_o= "head start"

x_{A}(t) = x_{o} + v_{A}t\\x_B(t)=v_Bt \\

Remember: v_B>v_A

"cathching up means" that x_A(t)=x_B(t)

x_{o} + v_{A}t =v_Bt\\x_{o} = v_Bt -v_{A}t\\x_{o} = t(v_B-V_A)\\\frac{x_{o}}{v_B-V_A} =t, where \ v_B>v_A

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4. The diameters of bolts produced by a certain machine are normally distributed with a mean of 0.35 inches and a standard devia
slamgirl [31]

Answer:

25.25%

Explanation:

Mean diameter (μ) = 0.35 inches

Standard deviation (σ) = 0.03 inches

For any given diameter, X, the z-score is given by:

z=\frac{X-\mu}{\sigma}

For X= 0.37 inches:

z=\frac{0.37-0.35}{0.03}\\z=0.6667

A z-score of 0.6667 is equivalent to the 74.75-th percentile of a normal distribution.

Therefore, the percentage of bolts that will have a diameter greater than 0.37 inches is:

P(X>0.37) = 100 - 74.75\\P(X>0.37) = 25.25\%

3 0
3 years ago
HELP!!!
abruzzese [7]

17.7m/s

Explanation:

Given parameters:

Height of branch = 16m

Unknown:

Velocity before falling = ?

Solution:

We are going to use the appropriate motion equation to solve this problem.

The bird is falling in line with the action of gravity.

Initial velocity is 0 for the bird.

Let the velocity during flight = V;

 Then;

             V² = U²  + 2gH

since U = 0

      V² = 2gH

    V is the unknown velocity

     H is the height of fall

     g is the acceleration due to gravity

    V = √2gH = √ 2x9.8 x 16 = 17.7m/s

learn more:

Velocity brainly.com/question/4460262

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6 0
3 years ago
First extinguish a match or candle by blasting it violently. Why?​
Andreas93 [3]

Answer:

The wax vapor on burning candles could reignite the flame.

Explanation:

7 0
3 years ago
A divot is created _____.
STatiana [176]
I think it is when shot scrapes off the top of the turf

4 0
3 years ago
Read 2 more answers
If 34.7 g of O2 reacts with iron to form 79.34 g of iron oxide, how much iron was used in the reaction?
zhuklara [117]

Answer: B. 44.64 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Mass of reactants = mass of iron + mass of oxygen = mass of iron + 34.7 g

Mass of product = mass of iron oxide = 79.34 g

As Mass of reactants = Mass of product

mass of iron + 34.7 g = 79.34 g

mass of iron = 44.64 g

Thus 44.64 g of iron was used in the reaction

6 0
3 years ago
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