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ivann1987 [24]
3 years ago
10

Cars A and B are racing each other along the same straight road in the following manner:

Physics
1 answer:
zysi [14]3 years ago
8 0

Answer:

\frac{x_{o}}{v_B-V_A} =t

Explanation:

Represent the car's position as a function

x_o= "head start"

x_{A}(t) = x_{o} + v_{A}t\\x_B(t)=v_Bt \\

Remember: v_B>v_A

"cathching up means" that x_A(t)=x_B(t)

x_{o} + v_{A}t =v_Bt\\x_{o} = v_Bt -v_{A}t\\x_{o} = t(v_B-V_A)\\\frac{x_{o}}{v_B-V_A} =t, where \ v_B>v_A

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