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tester [92]
3 years ago
6

Which two quantities can be expressed using the same units?

Physics
1 answer:
lara [203]3 years ago
4 0
I think it’s 3. Work and energy
I’m so sorry if I’m wrong


Hope you found this helpful !
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A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len
ale4655 [162]

Answer:

(75 x 0.02) = 1.5 N

Explanation:

7 0
3 years ago
You must exert a force of 4.5 N on a book to slide it across a table. If you do 2.7J
hoa [83]

Answer: 0.6m

Explanation:

Given that:

force = 4.5 N

Work done = 2.7J

Distance moved by the book = ?

Since work is done when force is applied on an object over a distance, apply the formula:

work = force x distance

2.7J = 4.5N x distance

Distance = (2.7J / 4.5N)

Distance = 0.6 m

Thus, the book was moved 0.6 metres far

3 0
3 years ago
What would we do if we didn't have solar energy?
Anvisha [2.4K]

We would have to use wind or another source

8 0
3 years ago
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How does the electron-cloud model describe electrons?
Dominik [7]

Answer:

Yo, you just kind of answered it yourself. The Electron Cloud Model is the informal way of describing an atomic orbital.

Explanation:

The analogy of the cloud of electrons is really describing the groups of electrons orbiting around said atom. Depending on the atom, there will be many or few electrons orbiting around it on all sides which can resemble an all-encompassing cloud.

5 0
3 years ago
An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid
mariarad [96]

Explanation:

It is given that, An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid Y, along the straight line joining the centers of the asteroids. We need to find the ratio of their masses.

As they are in equilibrium, the force of gravity due to each other is same. So,

\dfrac{Gm_xM}{r^2}=\dfrac{Gm_yM}{r^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{m_y}=(\dfrac{r_x^2}{r_y^2})\\\\\dfrac{m_x}{m_y}=(\dfrac{140^2}{481^2})\\\\\dfrac{m_x}{m_y}=0.0847

So, the ratio of masses X/Y is 0.0847

5 0
3 years ago
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