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2 years ago

Which two quantities can be expressed using the same units?

Physics

1 answer:

lara [203]2 years ago

4 0

I think it’s 3. Work and energy
I’m so sorry if I’m wrong

Hope you found this helpful !

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During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxima

vova2212 [387]

Answer:

The value $F = 0.1396 \ N$

Explanation:

From the question we are told that

The volume blood ejected is $V = 65 \ cm^3 = 65*10^{-6} \ m^3$

The velocity of the blood ejected is $v = 103 \ cm/s = \frac{103}{100} = 1.03 \ m/s$

The density of blood is $\rho = 1060 \ kg/m^3$

The heart beat is $R = 59 \ bpm(beats \ per \ minute) = \frac{59}{60}= 0.9833\ bps$

The average force exerted by the blood on the wall of the aorta is mathematically represented as

$F = 2 * \rho * V * R * v$

=> $F = 2 * 1060 * 65*10^{-6} * 0.9833 * 1.03$

=> $F = 0.1396 \ N$

8 0

2 years ago

A child sleds down a hill with an acceleration of 2.94 m/s2. If her initial speed is 0.0 m/s and her final speed is 17.5 m/s, ho

hram777 [196]

Answer:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

Explanation:

Given that the child accelerates uniformly and that both initial ( $v_{o}$ ) and final speeds ( $v_{f}$ ), measured in meters per second, and acceleration ( $a$ ), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom ( $t$ ), measured in seconds, is:

$t = \frac{v_{f}-v_{o}}{a}$ (1)

If we know that $v_{o} = 0\,\frac{m}{s}$ , $v_{f} = 17.5\,\frac{m}{s}$ and $a = 2.94\,\frac{m}{s^{2}}$ , then the time taken is:

$t = \frac{17.5\,\frac{m}{s}-0\,\frac{m}{s} }{2.94\,\frac{m}{s^{2}} }$

$t = 5.952\,s$

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

8 0

2 years ago

Use this formula to solve this problem:

Maslowich

Well, you gave us the formula to calculate power from work and time,
but you didn't give us the formula for work. We have to know that.

   Work = (force) x (distance)

The work to raise Sara to the top of the hill is

   Work = (300 N) x (15 meters)

   = 4,500 newton-meters = 4,500 joules .

Now we're ready to use the formula that you gave us. (Thank you.)

Power = (work) / (time)

= (4,500 joules) / (10 seconds)

450 joules/second = 450 watts.

6 0

3 years ago

Read 2 more answers

A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec

olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

$h=u't+\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}\times 9.8\times (4.3)^2$

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0

2 years ago

Which statement describes how work and power are similar?

postnew [5]

The statement that describes how work and power are similar is D. you must know time and energy to calculate both.
I am not completely sure though, so I hope this helps. :)

6 0

2 years ago

Read 2 more answers