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Zolol [24]
3 years ago
8

Give at least two reasons today’s astronomers are so interested in the discovery of additional Earth-approaching asteroids.

Physics
1 answer:
blondinia [14]3 years ago
4 0

Answer:

1. Potential hazard

2. Mining opportunity

Explanation:

The two reason, why astronomers are so interested in the discovery of additional Earth-approaching asteroids:

1. Potential hazard: We have proof that the dinosaurs got extinct because of an asteroid/comet strike on Earth. Also we have seen the effects of the Tunguska event and Chelyabinsk tragedy. These are enough to show us that asteroids can be very dangerous and wipe out the life from Earth.

2. Mining Opportunity: We have discovered a lot of asteroids which contains a lot of metal and precious elements. There can be a possibility of mining such asteroids in the future and reducing the burden on Earth.

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It's also known as a stationary wave. 
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4 years ago
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Can track storms at different altitudes
OlgaM077 [116]

<em><u>The radars, weather satellites and the several highly accurate barometers are used to track the different storms at different altitudes. </u></em>

Further Explanation:

The storms at different altitudes are generated due to pressure variation in the different regions of the air. This pressure variation in the air is the main cause of the formation of the storms.

These storms can be easily tracked by means of the Radars and other weather forecasting satellites which keep a track of the variation in the trends of the pressure and temperature in the particular regions.

The trends of the strength of the winds can also predict a lot about the direction of motion of the winds. The highly accurate barometers are used to measure the strength of the storms originating at the different altitudes.

Thus, <em><u>the radars, weather satellites and the several highly accurate barometers are used to track the different storms at different altitudes. </u></em>

<em><u> </u></em>

Learn More:

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Pressure

Keywords:

Storms, weather forecast, satellite, barometer, radars, tracking a storm, different altitudes, pressure variations, temperature, winds, measure.

3 0
4 years ago
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Can someone explain and slove question 4
Sonbull [250]
A. NaOH
B. PbNO3
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D. P2O3
E. CSe2
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6 0
3 years ago
A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

8 0
3 years ago
A box of spherical jawbreaker candies is 23 g and its volume is 32.3 cm3. If the average mass of a single jawbreaker is 0.94 g,
Alex777 [14]

The radius of each jawbreaker is approximately 0.68 cm.

<h3>Volume of a sphere;</h3>
  • v = 4 /3 πr³

where

r = radius

Therefore,

23 g  = 32.3 cm³

0.94 g  = ?

cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

Therefore,

volume of each jawbreaker = 4 /3 πr³

1.32 = 4 / 3 × 3.14 × r³

r³ = 1.32 /4.18666666667

r³ = 0.31533683707

r = ∛0.31533683707

r = 0.680651651 = 0.68

Therefore, the radius of each jawbreaker is approximately 0.68 cm.

learn more on radius here: brainly.com/question/19172427

5 0
3 years ago
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