I believe the correct answer is the first option. The primary difference between 3g and 4g cellular systems would be that 4g systems have faster transmission as compared to 3g. The G would mean generation. The very difference of both is their speeds.
Answer:
The correct answer to the following question will be "Adaptive Optics".
Explanation:
- AO (Adaptive Optics) is a technique used to enhance optical system performance by reducing the impact of incoming gravitational wave distortions by compressing a mirror to compensate for the distortion.
- It operates by calculating and compensating for defects in a wave-front with a system that corrects these errors as a deformable mirror or even a liquid crystal collection.
- It is a technique that can make it possible for a single ground-based telescope to get images as clear as that of the Hubble Space Telescope.
- Certain methods can achieve power resolution that exceeds the limit set by atmospheric distortion, for example, Aperture synthesis, Lucky imaging, and Speckle imaging.
Therefore, Adaptive Optics is the right answer.
Answer:
- def Lambda(strList):
- return list(filter(lambda s: (s.startswith("e")), strList))
-
- print(Lambda(["meaning", "cart", "engine", "egg"]))
Explanation:
The solution code is written in Python 3.
Lambda function is an anonymous function. It is a function without any name and it is started with keyword lambda. To write a lambda function to filter the string started with an 'e', we can write a lambda expression, s.startswith("e") that work on one input strList. If any word from strList started with letter "e", the word will be added into a list generated by filter function. At the end, the Lambda function will return the list of strings as output.
When we test the Lambda function using the sample string list (Line 4), we shall get ['engine', 'egg'] printed to terminal.
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
Answer:
The oldest malware vector was emails.
Explanation:
Websites were not widespread early on into the internet, however it was very easy to have a virus that uses an email contact list, where it can send itself to other email addresses and spread.
