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Tanya [424]
3 years ago
5

a spinner is divided into five equal sections labeled 1 to 5. What is the probability that the spinner will land on 3?

Mathematics
2 answers:
Svetlanka [38]3 years ago
6 0

Answer: \dfrac{1}{5}

Step-by-step explanation:

Given : A spinner is divided into five equal sections labeled 1 to 5.

Thus , the total number of sections on the spinner =5

Number of favorable outcomes =1

Then , the probability that the spinner will land on 3 is given by :-

\dfrac{\text{Favorable outcome}}{\text{Total outcomes}}\\\\=\dfrac{1}{5}

Hence, the probability that the spinner will land on 3 is \dfrac{1}{5}

andreev551 [17]3 years ago
3 0
Since there are 5 options, that's gonna be the denominator. And since there is only one number 3, 1 is our numerator. So the finish fraction is 1/5.

There is 1/5 probability that the spinner will land on 3.
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