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3 years ago

Solve m -2/12= 1/6A. 4B. 0C. 1D. 2

Mathematics

2 answers:

almond37 [142]3 years ago

7 0

The correct answer is B. 0

love history [14]3 years ago

4 0

$\dfrac{m-2}{12}=\dfrac{1}{6}\ \ \ |cross\ multiply\\\\6(m-2)=12\cdot1\\\\(6)(m)-(6)(2)=12\\\\6m-12=12\ \ \ |+12\\\\6m=24\ \ \ |:6\\\\m=4$

Answer: A. 4

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guajiro [1.7K]

Answer:

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3 years ago

A palindrome is a string whose reversal is identical to the string. How many bit strings of length n are palindromes?

alisha [4.7K]

Answer:

The number of palindromes is

$2^{\frac{n}{2} }$ when n is even and

$2^{\frac{n +1}{2} }$ when n is odd

Step-by-step explanation:

From the question we are told that

The length of the string is $n$

Generally palindrome is evaluated by considering the first part of a string

When the the length of the string is an even number then

it means that the first part of the string is $\frac{n}{2}$

Hence the number of bit strings of length n that are palindromes is evaluated as

$p(n_{even }) = 2^{\frac{n}{2} }$

But When the the length of the string is an odd number then

it means that the first part of the string is $\frac{n-1}{2}$

Hence the number of bit strings of length n that are palindromes is evaluated as

$p(n_{odd }) =2^{\frac{n -1}{2} +1 } = 2^{\frac{n +1}{2} }$

Generally each bit could be either 0 or 1

Hence the number of palindromes is

$2^{\frac{n}{2} }$ when n is even and

$2^{\frac{n +1}{2} }$ when n is odd

4 0

3 years ago

ANSWER ASAP PLEASE

yulyashka [42]

The answer is D, 32pi

The radius is half the diameter, which is 32. The circumference equation is $2\pi r$ or $\pi d$

So that gives you 32pi

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3 years ago

Determine the range of the following graph

Ierofanga [76]

Given:

The graph of a function is given.

To find:

The range of the graph.

Solution:

We know that, the domain is the set of input values and range is the set of output values.

In a graph, domain is represented by the x-axis and range is represented by the y-axis.

From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).

The graph of the function is defined over the interval $-8$ . So, the domain is (-8,3].