no because pendas means parentheses multiplication division left to right addition subtraction left to right
The minimum and maximum amounts that the artist received for her products are 278 and 322
<h3>Part A: Define a variable and write an
absolute value equation to represent the scenario.</h3>
Let the number of prints remaining be x.
The given parameters are:
Total = 300
Amount = 22 within her goal
So, we have the following absolute value equation
|x - 300| = 22
<h3>Part B: Solve the equation, showing all steps.</h3>
In (a), we have:
|x - 300| = 22
Remove the absolute bracket
x - 300 = 22 and x - 300 = -22
Add 300 to both sides
x = 322 and x = 278
<h3>Part C: What are the minimum and maximum amounts that the artist received for her products?</h3>
The minimum and maximum amounts that the artist received for her products are 278 and 322
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Answer:
Step-by-step explanation:
Sin58 = opp/hyp
Sin58 = CB/14
CB = 14 × sin58°
CB = 11.9cm
Answer:
The correct option is B.
Step-by-step explanation:
According to AAS congruence rule, two triangles are congruent if two angles and a non included side are congruent to corresponding angles and side of another triangle.
We need two angles and a non included side, to use AAS postulate.
In option A, two sides and their inclined angle are congruent, therefore these triangles are congruent by SAS postulate and option A is incorrect.
In option B, two angles and a non included side are congruent, therefore these triangles are congruent by AAS postulate and option B is correct.
In option C, two angles and their included side are congruent, therefore these triangles are congruent by ASA postulate and option C is incorrect.
In option D, all sides are congruent, therefore these triangles are congruent by SSS postulate and option D is incorrect.
Answer:
Step-by-step explanation:
<u>Solving with one operation at each step:</u>
- {362 – [63 + (48 ÷ 2) x 2]} + 3(9 +4) =
- {362 – [63 + 24 x 2]} + 3(9 +4) =
- [362 – (63 + 48)] + 3(9 +4) =
- (362 – 111) + 3(9 +4) =
- 251 + 3(13) =
- 251 + 39 =
- 290
