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3 years ago

Moira said, "If a right triangle has one side with a length of 3 units and one side with a length

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

If the two sides with length 3 and 4 are the two legs, then the missing side, i.e. the hypotenuse, is indeed 5.

But it could also be the case that 4 is the hypotenuse and 3 is one of the legs. In this case, the missing side is the other leg, so we calculate it using

$\sqrt{4^2-3^2}=\sqrt{16-9}=\sqrt{7}$

So, a right triangle with legs $\sqrt{7}$ and 3 has an hypotenuse of 4.

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Answer:

Step-by-step explanation:

We need common denominator, which in this case is 40.

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2 years ago

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Answer:

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2 years ago

Within a computer service company, 20 percent of the male employees and 30 percent of the female employees attend night school.

Maksim231197 [3]

26% of all the employees attend night school

Step-by-step explanation:

The given is:

Within a computer service company, 20 percent of the male employees and 30 percent of the female employees attend night school

40 percent of all employees are male

We need to find what percent of all the employees attend night school

Assume that the number of all employees is x

∵ The company has x employees

∵ 40 percent of all employees are male

- Find 40% of x

∵ 40% × x = $\frac{40}{100}$ × x = 0.4 x

∴ The number of the male employees is 0.4 x

- Subtract 0.4 x from x to find the number of the female employees

∵ The number of female employees = x - 0.4 x = 0.6 x

∴ The number of the female employees is 0.6 x

∵ 20 percent of the male employees attend night school

- Multiply 20% by 0.4 x to find the number of male employees

who attend night school

∴ The number of male who attend night school = 20% × 0.4 x

∴ The number of male who attend night school = $\frac{20}{100}$ × 0.4 x

∴ The number of male who attend night school = 0.08 x

∵ 30 percent of the female employees attend night school

- Multiply 30% by 0.6 x to find the number of female employees

who attend night school

∴ The number of female who attend night school = 30% × 0.6 x

∴ The number of male who attend night school = $\frac{30}{100}$ × 0.6 x

∴ The number of male who attend night school = 0.18 x

Add the number of male and female who attend night school

∵ 0.08 x + 0.18 x = 0.26 x

∴ The number of male and female who attend night school is 0.26 x

- Find the percentage of 0.26 x of x

∵ $\frac{0.26x}{x}$ × 100% = 26%

∴ 26% of all the employees attend night school

26% of all the employees attend night school

Learn more:

You can learn more about the percentage in brainly.com/question/6871421

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