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garri49 [273]
3 years ago
13

Moira said, "If a right triangle has one side with a length of 3 units and one side with a length

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

If the two sides with length 3 and 4 are the two legs, then the missing side, i.e. the hypotenuse, is indeed 5.

But it could also be the case that 4 is the hypotenuse and 3 is one of the legs. In this case, the missing side is the other leg, so we calculate it using

\sqrt{4^2-3^2}=\sqrt{16-9}=\sqrt{7}

So, a right triangle with legs \sqrt{7} and 3 has an hypotenuse of 4.

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PLEASE HELP ME ASAP!
AleksandrR [38]

Ok so first we find the equation that equals one variable.


2y = -x + 9

3x - 6y = -15


We solve for y.


2y = -x + 9

y = -x/2 + 9/2


Then we plug in this y value into the other equation to keep only one variable so we can solve for it.


3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18


Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.


y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3


Your answer would be (-28/3, -3/18)


Hope this helps!

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