<u>Answer:</u>
I am writing <em>partial code in</em> <em>c++ to calculate weighted average</em>. The weighted average should be calculated based on multiplying the test score and its <em>respective weight and finally add all the test score.</em>
<u>Explanation:</u>
<em>int arrtestscore[100];</em>
<em>int arrweight[100];</em>
<em>int n;</em>
<em>double weightedavg;</em>
<em>cout<<”Enter the number of test score for which weighted average needs to be calculated”;</em>
<em>cin>>n;</em>
<em>for(int x = 0; x <n;x++)</em>
<em>{</em>
<em> cout<<”Enter test score :” + (x+1) ;</em>
<em> cin>>arrtestscore[x];</em>
<em> count<<”Enter the respective weight:”;</em>
<em> cin>>arrweight[x];</em>
<em>}</em>
<em>for (int i=0; i<n;i++)</em>
<em>{</em>
<em> weightedavg = weightedavg + (arrtestscore[i] * arrweight[i])</em>
<em>}</em>
<em>cout<<”weighted average = “ <<weightedavg; </em>
Answer:
Capa de Internet. La capa de Internet, también conocida como capa de red o capa IP, acepta y transfiere paquetes para la red. Esta capa incluye el potente Protocolo de Internet (IP), el protocolo de resolución de direcciones (ARP) y el protocolo de mensajes de control de Internet (ICMP).
Explanation:
C. The laptop would be too far away from the source of the signal.
Answer:
Check the explanation
Explanation:
• We are taking a look at the class B network beginning with 172.0.0.0.0,while Converting this value to binary as:10101100.00010100.00000000.00000000. 32 bits in total, out of this the First 16 bits that are used as network ID and the subsequent 16 bits are used as HostID.Out of the 16 bits that are sued for Network ID the 2 bits namely Bits fifteen and sixteen (15 and 16) have been set and can't be changed and hence only 14 bits are used as network ID.
• Now so that we can divide this network into 50 subnets for class B network we will have to borrow a bit as shown below:
• 10101100.00010100.00000000.00000000=172.0.0.0.0,Adding 1 bit by borrowing from host portion and adding it to network ID will give it 10101100.00010100.00000000.00000000(0 shown in bold) or10101100.00010100.10000000.00000000 (1 shown in bold) will give us 2 unique subnets.i.e changing 1 bit will give us 2 power 1=2 subnets,thus changing 2 bits will give us 2 power 2 subnets =4 similarly changing 6 bits will give us 64 unique subnets.
• Which means and going by the above problem statement in case we need 50 subnets and we also need to change 6 bits in the Network ID to give 50 unique subnets.
• Thus the answer is 6
Answer:
Option B, C, and D is the correct options to the following question.
Explanation:
Because the joined report is that type of report which consists of the different standards of data or custom method types of report, in which user can add new accounts to the joined account or report. The joined reports do not support the display filter to the rows and it also not support the bucket field and the cross filters. So, that's why the following option is true.
