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PSYCHO15rus [73]
3 years ago
5

Pls answer will give brainlest dont answer if you dont know Upload your 300-word essay containing the following: the definition

of methane an explanation of how it is produced a description of how methane can be used as an energy source an explanation of how farmers are using methane from farm animals as an energy source a specific example of an actual farm where this system is being used
Computers and Technology
1 answer:
Rainbow [258]3 years ago
6 0

Answer: oh hello human :) also PLEASE DONT KILL ME I’m answering this because the question was already answered already on another post

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The standing toe touch is most likely to result in
Alecsey [184]
The correct answer is D
4 0
3 years ago
The is_positive function should return True if the number received is positive, otherwise it returns None. Can you fill in the g
poizon [28]
<h2>Question:</h2>

The is_positive function should return True if the number received is positive, otherwise it returns None. Can you fill in the gaps to make that happen?

<em>def is_positive(number):</em>

<em>        if  _____ :</em>

<em>            return _____</em>

<em />

<h2>Answer:</h2>

def is_positive(number):

   if (number > 0):

       return True

  else:

       return "None"

---------------------------------------------------------------------------------

<h2><u>Code Test and Sample Output:</u></h2>

print(is_positive(6))

>> True

print(is_positive(-7))

>> None

<h2></h2><h2> </h2>

----------------------------------------------------------------------------------

<h2><u>Explanation:</u></h2><h2><u></u></h2>

The code above has been written in Python.

Now, let's explain each of the lines of the code;

Line 1: defines a function called <em>is_positive </em>which takes in a parameter <em>number. </em>i.e

<em>def is_positive(number):</em>

<em />

Line 2: checks if the number, supplied as parameter to the function, is positive. A number is positive if it is greater than zero. i.e

<em>if (number > 0):</em>

<em />

Line 3: returns a boolean value <em>True </em> if the number is positive. i.e

<em>return True</em>

<em />

Line 4: defines the beginning of the <em>else</em> block that is executed if the number is not positive. i.e

<em>else:</em>

Line 5: returns a string value "None" if the number is not positive. i.e

<em>return "None"</em>

<em />

All of these put together gives;

===============================

<em>def is_positive(number):</em>

<em>    if (number > 0):</em>

<em>        return True</em>

<em>    else:</em>

<em>        return "None"</em>

<em>================================</em>

An example test of the code has also been given where the function was been called with an argument value of 6 and -7. The results were True and None respectively. i.e

print(is_positive(6))   = True

print(is_positive(-7))  = None

8 1
3 years ago
Read 2 more answers
Asia pacific and Japanese sales team from cloud kicks have requested separate report folders for each region.The VP of sales nee
MaRussiya [10]

Answer:

B) Create all new regional folders and move the reports to the respective region folder with viewer access.

Explanation:

Below are the options

A) Create grouped folders, keeping the top region folder sharing settings and limiting the sharing settings for the grouped folders for each region.

B) Create all new regional folders and move the reports to the respective region folder with viewer access.

C) Create all new regional folders and move the reports to the respective region folder with subscribe access.

D) Create subfolders, keeping the top region folder sharing settings and limiting the sharing settings for the subfolders for each region

In order to required reports at one place and also wants to retain the visibility for each folder the consultant should suggest that all new regional folders should be created and afterwards it would be moved to their relevant region folders by involving the viewer access feature so that the VP should access it anytime

Hence, the correct option is B.

3 0
4 years ago
A device that is connected to a network that is identified by a unique number and works as an individual part of the network is
VMariaS [17]
Cellular phone? I'm pretty sure

7 0
3 years ago
write a mips program that runs on SPIM that allows the user to enter the number of hours, minutes and seconds and then prints ou
adell [148]

Answer:

The mips program will be as:

.MODEL SMALL

.STACK 100H

.DATA

  PROMPT_1  DB  \'Enter the time in seconds up to 65535 = $\'

  PROMPT_2  DB  0DH,0AH,\'The time in hh:mm:ss format is = $\'

  SEPARATOR DB  \' : $\'

.CODE

  MAIN PROC

    MOV AX, @DATA                ; initialize DS

    MOV DS, AX

    LEA DX, PROMPT_1             ; load and display the string PROMPT_1

    MOV AH, 9

    INT 21H

    CALL INDEC                   ; call the procedure INDEC

    PUSH AX                      ; puah AX onto the STACK

    LEA DX, PROMPT_2             ; load and display the string PROMPT_2

    MOV AH, 9

    INT 21H

    POP AX                       ; pop a value from STACK into AX

    XOR DX, DX                   ; clear DX

    MOV CX, 3600                 ; set CX=3600

    DIV CX                       ; set AX=DX:AX\\CX , DX=DX:AX%CX

    CMP AX, 10                   ; compare AX with 10

    JGE @HOURS                   ; jump to label @HOURS if AX>=10

    PUSH AX                      ; push AX onto the STACK

    MOV AX, 0                    ; set AX=0

    CALL OUTDEC                  ; call the procedure OUTDEC

    POP AX                       ; pop a value from STACK into AX

    @HOURS:                      ; jump label

    CALL OUTDEC                  ; call the procedure OUTDEC

    MOV AX, DX                   ; set AX=DX

    PUSH AX                      ; push AX onto the STACK

    LEA DX, SEPARATOR            ; load and display the string SEPARATOR

    MOV AH, 9

    INT 21H

    POP AX                       ; pop a value from STACK into AX

    XOR DX, DX                   ; clear DX

    MOV CX, 60                   ; set CX=60

    DIV CX                       ; set AX=DX:AX\\CX , DX=DX:AX%CX

    CMP AX, 10                   ; compare AX with 10

    JGE @MINUTES                 ; jump to label @MINUTES if AX>=10

    PUSH AX                      ; push AX onto the STACK

    MOV AX, 0                    ; set AX=0

    CALL OUTDEC                  ; call the procedure OUTDEC

    POP AX                       ; pop a value from STACK into AX

    @MINUTES:                    ; jump label

    CALL OUTDEC                  ; call the procedure OUTDEC

    MOV BX, DX                   ; set BX=DX

    LEA DX, SEPARATOR            ; load and display the string SEPARATOR

    MOV AH, 9

    INT 21H

    MOV AX, BX                   ; set AX=BX

    CMP AX, 10                   ; compare AX with 10  

    JGE @SECONDS                 ; jump to label @SECONDS if AX>=10

    PUSH AX                      ; push AX onto the STACK  

   MOV AX, 0                    ; set AX=0

    CALL OUTDEC                  ; call the procedure OUTDEC

    POP AX                       ; pop a value from STACK into AX

    @SECONDS:                    ; jump label

    CALL OUTDEC                  ; call the procedure OUTDEC

   MOV AH, 4CH                  ; return control to DOS

    INT 21H

  MAIN ENDP

7 0
3 years ago
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