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4 years ago

How much water should we add to 35kg of sugar syrup to change it's concentration from 30% to 25%

Mathematics

1 answer:

agasfer [191]4 years ago

4 0

Answer:

Water = 1/5 of the volume of the syrup

Step-by-.step explanation:

Suppose we had 1000 cm^3 of syrup and the new volume after adding water is x cm^3. Now the amount of sugar stays the same so we have the equation 35 * 1000 = 25 * x

x = (30 * 1000) / 25 = 30,000 / 25

= 1200 cm^3

So we need to add 200 cm^2 of water .

In general terms, we need to add water which equals 1/5 of the volume of the syrup,

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Deion has 3/4 pound bag of dog treats. He will give his dog 1/8 of the treats after they play each day. How many days will the b

kirza4 [7]

3/4=6/8

1/8+1/8+1/8+1/8+1/8+1/8

=6(1/8)

=6/8

Answer: 6 days.

8 0

4 years ago

The table below shows some inputs and outputs of the invertible function f etc

Snowcat [4.5K]

Answer:

$(a)\ f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)=0$

Step-by-step explanation:

Given

The attached table

$(a)\ f^{-1}(-15)$

This represents an inverse function.

So, we look into x row for its value.

i.e.

$f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)$

Just like (a)

$f^{-1}(4) = -11$ ---- by looking into the x rows

$f(9) = 11$

So:

$f^{-1}(4) + f(9)=-11 + 11$

$f^{-1}(4) + f(9)=0$

4 0

3 years ago

If (5-3i)(x+iy)/(4-5i) = (2+i)^2-(3-4i)^2, then x=___ and y=____

Leona [35]

This looks complicated

lets simplify both sides

By multiplying top and bottom by the conjugate:-

left side = (5-3i)(x + iy) (4+5i) (5-3i)(x + iy) (4+5i)
------------------------ = ------------------------
(4-5i)(4+5i) 41

right side = (2 + i + 3-4)(2+i - 3 + 4i) (by Difference of 2 squares)

= 5-3i)(-1 + 4i)

so as left side = right side

(5-3i)(x+yi)(4+5i) = 41 (5-3i)(-1+5i)

5-3i is common so:-

(x + iy)(4+5i) = 41(-1+5i)

4x +5xi + 4yi - 5y = -41 + 205i

4x - 5y + (5x + 4y)i = -41 + 205i

EQuating coefficients we are left with the system of equations

4x - 5y = -41
5x + 4y = 205

solving this gives x = 21 and y = 25

8 0

3 years ago

The measure of HMQ is (4x – 20)° ?

Kipish [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the distance between the point - 3, 2 and 1 - 1

dusya [7]

Answer:

5 units

Step-by-step explanation:

Find the distance between the point - 3, 2 and 1 - 1

Given data

x1= -3

y1= 2

x2= 1

y2= -1

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

subtitute

d=√((1-(-3))²+(-1-(2))²)

d=√((1+3))²+(-1-2))²)

d=√((4)²+(-3))²)

d=√16+9

d=√25

d=5

Hence the distance between the points is 5 units

7 0

3 years ago