For any polynomial with a complex root, the imaginary part of the complex root always has positive and negaive component. Since one of the roots of this polynomial is 6i, then -6i must also be a root of the function.
Answer:
Option B is correct
Step-by-step explanation:
Given is a cos funciton.
Period = 3
Max = 20 and minimum =0
Hence centre line is y = 1/2 (max+min)
i.e. y =10 is the central line
Let the funciton be of the form
y = a cos (bx+C)+d
We got d = 10...i
Period =3
Hence b =
... ii
Amplitude = a = distance of max from central line = 20-10 =10...iii
Since reflection over x axis, sign of a =negative
a=-10
Since no horizontal shift, c=0 ... iv
Put to gether the function is

Answer:
4000 rupees
Step-by-step explanation:
20000×10×2/100
= 4000 rupees
No. It's rational. The solutions are +10 and -10.
The equation is "x=0", because the x intercepts at the x axis with no y-intercept.