Answer- KG⎯∥JH⎯
the given figure is a trapezium in which CF||DE
Reflection of figure CDEF and shifting it by 3 units does not change the shape of the figure but changes only its position in the x-y plane.
so, the shape of the figure GHJK will be same as that of CDEF.
so sides, KG⎯∥JH⎯
Answer:
w=7.
Step-by-step explanation:
Divide 7 on both sides of the equation.
Answer:
QR = 17 cm
Step-by-step explanation:
Δ RST is a 5- 12- 13 triangle with hypotenuse RT = 13 cm , then
TS = 5 cm and PT = 2 × 5 = 10 cm
So PS = 10 + 5 = 15 cm
PS is parallel to the vertical line from vertex Q and intersects the horizontal line projected from SR of length 20 - 12 = 8 cm
Using the right triangle formed calculate QR using Pythagoras' identity
QR² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )
QR = 
= 17
Answer: $ 57.80
Step-by-step explanation:
Answer:
x = 1/2y + 1
y = 2x - 2
Step-by-step explanation:
Let's solve for x.
4x−2y=4
Step 1: Add 2y to both sides.
4x−2y+2y=4+2y
4x=2y+4
Step 2: Divide both sides by 4.
4x
4
=
2y+4
4
x=
1
2
y+1
Answer:
x=
1
2
y+1
Let's solve for y.
4x−2y=4
Step 1: Add -4x to both sides.
4x−2y+−4x=4+−4x
−2y=−4x+4
Step 2: Divide both sides by -2.
−2y
−2
=
−4x+4
−2
y=2x−2
Answer:
y=2x−2
Hope this helps!
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