Question

The sum of three numbers is 103. The second number is 7 more than the first. The third number is 3 times the second. What are the numbers

Answer 1

Answer: 15,22 and 66

Step-by-step explanation: Call the numbers a,b and c.

Their sum is 103 so a+b+c=103

The second number is 7 more than the first so b=a+7

The third number = 3 times the second so c=3b

Now replace c with 3b in the top equation, so a+b+3b=103, which becomes a+4b=103

Now replace b with a+7, so a+4(a+7)=103. This solves to give a=15

b=a+7 so b=22 and c=3b so c=66