Question

Solve: a 100-mL pitcher of lemonade is currently 90% water and 10% lemon concentrate. How much water must you add to change the ballance to 95% water and 5% lemon concentrate.

Answer 1

Answer:

Must add 100 milliliters of water

Step-by-step explanation:

Let

x ----> milliliters of water to add

we know that

Originally

The milliliters of lemon concentrate is equal to the 10% of 100 mL

so

$0.10(100)=10\ mL$

Now

The balance of lemon concentrate is equal to 5%

The milliliters of lemon concentrate is the same

so

$0.05(100+x)=10$

solve for x

$5+0.05x=10$

$x=100\ mL$

therefore

Must add 100 milliliters of water