Answer:
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- <u><em>Yes, it is reasonable to expect that more than one subject will experience headaches</em></u>
Explanation:
Notice that where it says "assume that 55 subjects are randomly selected ..." there is a typo. The correct statement is "assume that 5 subjects are randomly selected ..."
You are given the table with the probability distribution, assuming, correctly, the binomial distribution with n = 5 and p = 0.732.
- p = 0.732 is the probability of success (an individual experiences headaches).
- n = 5 is the number of trials (number of subjects in the sample).
The meaning of the table of the distribution probability is:
The probability that 0 subjects experience headaches is 0.0014; the probability that 1 subject experience headaches is 0.0189, and so on.
To answer whether it <em>is reasonable to expect that more than one subject will experience headaches</em>, you must find the probability that:
- X = 2 or X = 3 or X = 4 or X = 5
That is:
- P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5).
That is also the complement of P(X = 0) or P(X = 1)
From the table:
- P(X = 0) = 0.0014
- P(X = 1) = 0.0189
Hence:
- 1 - P(X = 0) - P(X = 1) = 1 - 0.0014 - 0.0189 = 0.9797
That is very close to 1; thus, it is highly likely that more than 1 subject will experience headaches.
In conclusion, <em>yes, it is reasonable to expect that more than one subject will experience headaches</em>
Answer:
31
Step-by-step explanation:
A negative negative is a positive
12- (-19)
12+19
31
If there were 37 apples. One of your friends took 5 apples. You divided the leftover apples and gave it to your four friends. How many apples did each of the four friends get?
x=8
37-5=32
32/4=8.
Answer:
6x-11y=-13
Step-by-step explanation:
(x1,y1)=(3/2,2) and (x2,y2)=(-4,-1)
y-y1= y2-y1/x2-x1 (x-x1)
y-2=-3/-11/2(x-3/2)
=6/11(x-3/2)
11(y-2)=6x-9
11y-22=6x-9
6x-11y=9-22
6x-11y=-13
