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3 years ago

EFGH is translated 3 units to the left and 7 units up. What are the coordinates of H'?

Mathematics

2 answers:

Nikitich [7]3 years ago

8 0

Where was H originally?

Kazeer [188]3 years ago

8 0

Answer:

A (3,5)

Step-by-step explanation:

A.P.E.X. Approved

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Which reason justifies step 2 in the proof

tigry1 [53]

<h3>Answer: C. If two lines are parallel, then the alternate interior angles formed are congruent.</h3>

This is through the alternate interior angles theorem. Angles Q and T pair up as one alternate interior set of angles that are the same measure. The same thing applies to angles X and R.

The identical arrow markers on segments XQ and TR show that those segments are parallel. Segment TQ is one transversal cut (forming alternate interior angles Q and T). Segment XR is the other transversal cut (forming alternate interior angles X and R).

We could say "angle XRT" or "angle TRX" instead of "angle R", though its ideal to use shortcuts whenever possible. The same applies for the other angles as well.

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3 years ago

Help Please I Don’t Understand

Nat2105 [25]

Answer: -4x+5>-5=x>2.5

-25>-5(x+2.5)=x<2.5

Step-by-step explanation:

-4x+5>-5 -25>-5(x+2.5)

-5 -5 -25>-5x-12.5

-4x>-10 +12.5 +12.5

/-4 /-4 -12.5>-5x

x>2.5 /-5 /-5

2.5>x

x<2.5

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3 years ago

Marissa painted 1/2 of her bedroom and 3/4 ton an hour at this rate how long would it take her to paint the entire room A. 3/ 8

Nikitich [7]

Answer:

A. 3/8 of an hour

Step-by-step explanation:

if she is not a slacker

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2 years ago

Figure ABCD is a square. Prove BD ≅ AC. Statements Reasons 1. ABCD is a square 1. given 2. ∠DAB, ∠ABC, ∠BCD, and ∠CDA are right

FromTheMoon [43]

A. all sides are congruent. :)

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2 years ago

Read 2 more answers

Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

motikmotik

Given:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

Coordinates of the point A':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point A(-2,3), we get;

$(-2,3)\rightarrow (-2,-3)$

Thus, the coordinates of the point A' is (-2,-3)

Coordinates of the point B':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point B(0,3), we get;

$(0,3)\rightarrow (0,-3)$

Thus, the coordinates of the point B' is (0,-3)

Coordinates of the point C':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point C(-1,-1), we get;

$(-1,-1)\rightarrow (-1,1)$

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

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3 years ago