Answer:
14/8 or 14:8
Step-by-step explanation:
blue:brown=14:8
Answer:
£107,714 > £107,674
Step-by-step explanation:
Given
£107,714 and £107,674
Required
Determine the relationship between them using > or <
From the given parameters, we understand that
£107,714 is greater than £107,674
The keyword greater than is represented mathematically with >
Hence:
£107,714 is greater than £107,674
becomes
£107,714 > £107,674
Answer: To clear an equation of decimals, multiply each term on both sides by the power of ten that will make all the decimals whole numbers. In our example above, if we multiply .25 by 100, we will get 25, a whole number. Since each decimal only goes to the hundredths place, 100 will work for all three terms.
So let's multiply each term by 100 to clear the decimals:
(100)0.25x + (100)0.35 = (100)(-0.29)
25x + 35 = -29
Now we can solve the equation as normal:
25x + 35 - 35 = -29 - 35
25x = -64
x = -2.56 Since the original was in decimal form, the answer should most likely also be in decimal form.
Let's look at one more:
1.75x + 4 = 6.2
We have to think a little more carefully about what multiple of ten to use here. 6.2 only needs to be multiplied by 10, but 1.25 needs 100, so we will multiply every term by 100. Don't forget to multiply the 4 by 100 as well.
(100)(1.75x) + (100)(4) = (100)(6.2)
175x + 400 = 620
We had to be extra careful as we multiplied by 100. Now we can solve the equation as normal:
175x + 400 - 400 = 620 - 400
175x = 220
x = 1.26
Step-by-step explanation:
Answer:
I thinks its SAS
Step-by-step explanation:
SAS is Two sides and included agale of one triangle congruent to two sides
Answer: 2 days
Step-by-step explanation:
The monkeys eat 3 ²/₃ buckets of bananas each day. Convert this to an improper fraction:
= 3²/₃ = 11/3 buckets per day
The zookeeper bought 7¹/₃ which is:
= 22/3 buckets
To find out the number of days the bananas will last, divide the buckets bought by the buckets eaten per day:
= 22/3 ÷ 11/3
= 22/3 * 3/11
= 66/33
= 2 days
<em>If dividing fractions, multiply by the reciprocal of the second fraction. </em>
