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3 years ago

7

Alex has a small notebook that is shaped like a rectangle. She knows one side is 6 cm and another side is 4 cm. Explain how to f

ind the distance around the notebook without using a ruler.

2 answers:

kkurt [141]3 years ago

8 0

Answer : The distance around the notebook is, 20 cm

Step-by-step explanation :

Given:

Length of rectangle = 6 cm

Breadth of rectangle = 4 cm

As we know that perimeter (distance) is the sum of all side of a given figure.

As there are 4 sides of rectangle.

Perimeter of rectangle = 2(Length + Breadth)

Perimeter of rectangle = 2(6 cm + 4 cm)

Perimeter of rectangle = 2(10 cm)

Perimeter of rectangle = 20 cm

Therefore, the distance around the notebook is, 20 cm

brilliants [131]3 years ago

5 0

6+6+4+4
Add all of the side lengths together.

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The length of a room is 4 feet less than twice its width. The perimeter of

AlladinOne [14]

L=2W-4

PERIMETER=2L+2W

58=2(2W-4)+2W

58=4W-8+2W

58=6W-8

6W=58+8

6W=66

W=66/6

W=11 ANS. FOR THE WIDTH.

L=2*11-4

L=22-4

L=18 ANS. FOR THE LENGTH.

PROOF:

58=2*18=2*11

58=36+22

58=58

5 0

3 years ago

Fernando has a bag of beads in five different colors: purple, blue, green, green, orange, and gray. The table below shows the re

zavuch27 [327]

Answer: 6

Step-by-step explanation:

6 0

3 years ago

In 2 years, you want to have $5000 in your savings account. Find the amount you should deposit if the account pays 3% annual int

muminat

The amount you should deposit is $4709.18

Step-by-step explanation:

The formula for compound interest, including principal sum is

$A=P(1+\frac{r}{n})^{nt}$ , where:

A is the future value of the investment/loan, including interest
P is the principal investment amount
r is the annual interest rate in decimal
n is the number of times that interest is compounded per unit t
t is the time the money is invested or borrowed for

∵ You want to have $5000 in your savings account in 2 years

∴ A = 5000

∴ t = 2

∵ The account pays 3% annual interest, compounded monthly

∴ r = 3% = 3 ÷ 100 = 0.03

∴ n = 12 ⇒ compounded monthly

- Substitute these values in the formula above

∴ $5000=P(1+\frac{0.03}{12})^{(12)(2)}$

∴ $5000=P(1+0.0025)^{24}$

∴ $5000=P(1.0025)^{24}$

- Divide both sides by $(1.0025)^{24}$

∴ P = 4709.18

The amount you should deposit is $4709.18

Learn more:

You can learn more about the compounded interest in brainly.com/question/2514241

#LearnwithBrainly

3 0

3 years ago

jek_recluse [69]

Man i don’t know
i really donttt

3 0

3 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago