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Katen [24]
3 years ago
13

The probability that a house in an urban area will develop a leak is 55​%. if 2020 houses are randomly​ selected, what is the pr

obability that none of the houses will develop a​ leak? round to the nearest thousandth.
Mathematics
1 answer:
k0ka [10]3 years ago
7 0
<span>The probability that a house in an urban area will develop a leak is 55​%. if 20 houses are randomly​ selected, what is the probability that none of the houses will develop a​ leak? round to the nearest thousandth.

Use binomial distribution, since probability of developing a leak,  p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000

</span>
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If you roll a 6-sided die 4 times, what is the probability of one roll being a multiple of 3? A)2/3 B)16/81 C)145/1296 D)65/81 E
DerKrebs [107]

Answer:

671/1296

The probability of rolling at least one six is therefore 1 − 625/1296 = 671/1296 ≈ . 517.

Step-by-step explanation:

4 0
3 years ago
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Please help this is due tomorrow ​
tia_tia [17]
Danielle had a percent error of 13.6 (farthest)
Iris had a percent error of 6.8
HB has a percent error of -2.3 (closest)

So the order is HB, Iris, and then Danielle
7 0
3 years ago
8x + 6 - 2x = 34 x= ?
e-lub [12.9K]
8x + 6 - 2x = 34x

Simplify 8x +6 - 2x to 6x + 6:
6x + 6 = 34x

Subtract 6x from both sides:
6 = 34x- 6x

Simplify 34x - 6x to 28x:
6 = 28x

Divide both sides by 28:
\frac{6}{28} = x

Simplify \frac{6}{28} to \frac{3}{14} :
\frac{3}{14} = x

Now switch sides and the answer is:

x = \frac{3}{14}

:) <3

5 0
3 years ago
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Need help of simplifying each sum or difference
dimaraw [331]
First you need to get a common denominator. The first two problems already have a common denominator, so you just have to find the sum and difference of the two problems, respectively. 

6.) (9y-3)/(y^2-5)

8.) 3/xy^3

Two find a common denominator, find the smallest value that has BOTH denominators as factors. 

10.) 8x^3*y^3 is the common denominator

Answer: 2/(8*x^3*y^3)

12.) Factor x^2 + 4x + 4 to get (x+2)(x+2)

Therefore, x+2 is already part of x^2 + 4x + 4

(x+4)/(x^2+4x+4)

14.) Factor both denominators..

4(y+2) and y(y+2)

So the common denominator would be 4y(y+2)

The first fraction is missing a "y" so multiply the numerator by y to get y^2

The second fraction is missing a "4" so multiply the numerator by 4 to get 4

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Answer: (y-2)/4y


6 0
3 years ago
I need help solving this problem
Alex787 [66]

Answer:

(x,f(x)) = (-1,8) -- Another point

a = 8

Step-by-step explanation:

Given

f(x) = a|x|

(x,f(x)) = (1,8)

Solving (a): Another point

Substitute 1 for x and 8 for f(x) in f(x) = a|x|

8 = a|1|

Remove absolute bracket

8 = a*1

8 = a

a = 8

Substitute 8 for a in f(x) = a|x|

f(x) = 8|x|

Let x = -1

f(x) = 8|-1|

Remove absolute bracket

f(x) = 8*1

f(x) = 8

So, another point is:

(x,f(x)) = (-1,8)

Solving (b): The value of a

This has been solved in (a) above

a = 8

7 0
3 years ago
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