Which of the terms cannot be combined with the others?<br><br> -3x<br> 4x 2<br> x<br> 11x

Work out the area of a semi circle take pi to be 3.142 and five your answer to two decimal places

Diano4ka-milaya [45]

Answer:

what are the measurements of the semi circle

Step-by-step explanation:

7 0

3 years ago

Help this is due tomorrow please! Carter has 88 feet of fencing to enclose a dog pen in his yard. He is trying to decide whether

svet-max [94.6K]

<h3>Answer:</h3>

The circle makes the larger area

The difference in the two areas is roughly 132.2479 square feet.

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Explanation:

If Carter decides to go for a circle, then 88 is the circumference, which is the distance around the circle (aka perimeter of the circle).

Use this to find the radius needed

C = 2*pi*r

r = C/(2pi)

r = 88/(2pi)

r = 44/pi

I'll leave it in exact form rather than approximate it.

Once we know the radius, we can find the area of the circle.

A = pi*r^2

A = pi(44/pi)^2

A = pi*(1936/(pi^2))

A = 1936/pi

A = 616.247939651819 approximately

I used my calculator's stored version of pi to compute the area in the final step.

We'll be comparing this number later, so hold onto it for now.

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If Carter instead decides for a square, then 88 is the perimeter since it's the amount of fencing he has to work with.

Divide it into 4 pieces to find the length of each side of the square (all sides are equal in a square)

88/4 = 22

Each side is 22 feet

The area of this square is (22)^2 = 22*22 = 484 square feet

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Summary:

If Carter goes for a circular enclosure, then he gets roughly 616.2479 square feet.
The square enclosure only gets him exactly 484 square feet.

The circle wins in terms of larger area.

The difference being roughly 616.2479 - 484 = 132.2479 square feet.

3 0

3 years ago

A cup of coffee with temperature 155degreesF is placed in a freezer with temperature 0degreesF. After 5 minutes, the temperatur

Leviafan [203]

Answer:

45.50° F

Step-by-step explanation:

As per Newton's law,

$T(t) = T_{s}+(T_{0} + T_{s})e^{-kt}$

When T(t) is the final temperature

$T_{s}$ = Temperature of surrounding

$T_{0}$ = Initial temperature

t =duration of cooling

k = constant

$103=0+(155-0)e^{-k\times 5}$

$103=155e^{-5k}$

Now take natural log on both the sides

$ln(103)=ln(155e^{-5k})$

$ln(103)=ln(155)+ln(e^{-5k})$

$ln(103)=ln(155)=-5k$

4.6347 - 5.0434 = -5k

$k=\frac{0.40872}{5}$

k = 0.0817

$T(t)=0+(155-0)e^{(0.0817\times 15)}$

= $155e^{-1.226}$

= 155 (02935)

= 45.49 ≈ 45.50° F

8 0

3 years ago

Using traditional methods, it takes 10.1 hours to receive a basic driving license. A new license training method using Computer

Law Incorporation [45]

Answer:

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:

Null hypothesis: $\mu =10.1$

Alternative hypothesis: $\mu \neq 10.1$

$t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990$

$p_v =2*P(t_{(11)}>0.990)=0.343$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=10.5$ represent the sample mean

$s=1.4$ represent the sample standard deviation

$n=12$ sample size

$\mu_o =10.1$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:

Null hypothesis: $\mu =10.1$

Alternative hypothesis: $\mu \neq 10.1$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=12-1=11$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(11)}>0.990)=0.343$

Conclusion

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.

7 0

3 years ago

Sarah can take no more than 22 pounds and I like the trap her suitcase weighs 112 ounces how many more pounds can she park witho

Leya [2.2K]

Answer:

15 pounds

Step-by-step explanation:

there are 16 ounces in one pound

so...

first find the limit in ounces

$22 = \frac{x}{16}$

because there are 16 ounces in every one pound you need to multiply 22 by 16

which is 352

now subtract what you already used

$352 - 112$

which is 240

now convert to pounds

$x = \frac{240}{16}$

which is 15

so 15 more pounds

3 0

3 years ago

Which of the terms cannot be combined with the others? -3x 4x 2 x 11x